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Location of rootsEdexcel International A Level Maths: Flashcards

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State the change-of-sign test for a root.

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State the change-of-sign test for a root.
If ff is continuous on [a,b][a,b] and f(a)f(a), f(b)f(b) have opposite signs, then f(x)=0f(x)=0 has a root in the interval.
What must you state about ff besides the sign change?
That ff is continuous on the interval.
Which function types are always continuous?
Polynomials, exe^x, sin⁡x\sin x, cos⁡x\cos x (and ln⁡x\ln x for x>0x>0).
Why does h(x)=1x−2h(x)=\frac{1}{x-2} fail the test on [1,3][1,3]?
It is not continuous at x=2x=2 (asymptote), so the sign change does not give a root.
Does f(a)f(a) and f(b)f(b) with the same sign prove there is no root?
No. There could be an even number of roots (or a repeated root) in the interval.
Show that x3+x−5=0x^3+x-5=0 has a root in [1,2][1,2]: what values?
f(1)=−3f(1)=-3 and f(2)=5f(2)=5: a change of sign.
How do you show a root is 3.53.5 to 1 d.p.?
Show a sign change between 3.453.45 and 3.553.55.
What unit must a calculator use for trigonometric roots?
Radians.
A root is found in [1.51,1.52][1.51,1.52]. What is it to 1 d.p.?
1.51.5
What does a repeated root, such as (x−2)2=0(x-2)^2=0, do to the sign?
It touches the axis without a sign change.
How many distinct roots can a cubic have at most?
Three.
What is a good first step to find an interval for a root?
Tabulate f(x)f(x) at integer values and look for a sign change.

Exam questions on Location of roots

  1. The function ff is defined by f(x)=x3+x−5f(x)=x^3+x-5 for x∈Rx\in\mathbb{R}. The equation f(x)=0f(x)=0 has exactly one real root α\alpha.
    Given that f(1.6)=0.696f(1.6)=0.696, explain how the values of f(1.5)f(1.5) and f(1.6)f(1.6) show that 1.5<α<1.61.5<\alpha<1.6.2 marks
  2. The functions hh and pp are defined by h(x)=1x−2h(x)=\frac{1}{x-2} for x≠2x\neq2, and p(x)=x2−2p(x)=x^2-2 for x∈Rx\in\mathbb{R}.
    A student notes that h(1)<0h(1)<0 and h(3)>0h(3)>0, and concludes that h(x)=0h(x)=0 has a root in [1,3][1,3]. Explain why this conclusion is wrong.2 marks
  3. The function ff is defined by f(x)=ex−3xf(x)=e^x-3x for x∈Rx\in\mathbb{R}. The equation f(x)=0f(x)=0 has two real roots, α\alpha and β\beta, with α<β\alpha<\beta.
    Show that α\alpha lies in the interval [0.5,0.7][0.5,0.7].3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).