EnzymesEdexcel A-Level Biology A: Revision notes
Section 1
Enzymes as biological catalysts
Enzymes are globular proteins that act as biological catalysts. They speed up metabolic reactions without being used up. Almost all reactions need energy to get started, called the activation energy. Enzymes provide an alternative reaction pathway with a lower activation energy, so more molecules have enough energy to react and the reaction is faster at body temperature.
An enzyme does not change the products or the final amount of product. It only changes how quickly the reaction happens.
Enzymes do not provide energy to a reaction. They lower the activation energy.
Section 2
The active site and specificity
The active site is a region of the enzyme with a specific three-dimensional shape, formed by the folding of the polypeptide (its tertiary structure). The molecule that binds is the substrate, and the two form an enzyme–substrate complex.
Enzymes are specific: only a substrate with a shape complementary to the active site can bind. If the tertiary structure changes, the active site changes shape and the enzyme no longer works.
In the induced-fit model, the active site changes shape slightly as the substrate binds, which strains the bonds in the substrate and so lowers the activation energy. This replaces the older, rigid lock-and-key model.
Section 3
Intracellular and extracellular enzymes
Intracellular enzymes are made in a cell and work inside it, for example catalase in liver cells breaking down hydrogen peroxide, or the enzymes of respiration.
Extracellular enzymes are made by cells but released to work outside them, for example amylase from the salivary glands and pancreas and trypsin from the pancreas. Digestive enzymes are extracellular because food molecules are too large to enter cells, so they are hydrolysed into small soluble molecules outside the cells and then absorbed.
Extracellular does not mean made outside the cell. The enzyme is made inside a cell and then secreted.
Section 4
Measuring the initial rate
The rate of an enzyme-controlled reaction is measured as the amount of product formed, or substrate used, per unit time. Rates are compared as initial rates, measured at the start, because later the substrate concentration falls and product builds up, which slows the reaction.
To find an initial rate, plot product (or substrate) against time and draw a tangent at time zero. The gradient of the tangent is the initial rate, for example in cm³ s⁻¹. Where only a quantity over a short time is available, the mean rate is the change divided by the time.
Worked example: 18 cm³ of oxygen in 30 s gives a mean rate of 18 ÷ 30 = 0.60 cm³ s⁻¹.
Section 5
Core practical 4: enzyme concentration
To investigate the effect of enzyme concentration, keep the substrate in excess and change only the enzyme concentration.
- Make different enzyme concentrations by diluting a stock solution.
- Control temperature with a water bath and pH with a buffer; use the same volume and concentration of substrate each time.
- Measure the product, for example oxygen from catalase and hydrogen peroxide collected in a gas syringe, over time.
- Calculate the initial rate for each concentration and repeat to find a mean.
The initial rate is directly proportional to enzyme concentration, because doubling the enzyme doubles the number of active sites.
Section 6
Core practical 4: substrate concentration
To investigate substrate concentration, use a fixed amount of enzyme and a dilution series of the substrate, for example amylase with starch measured with iodine solution and a colorimeter, using a calibration curve.
As substrate concentration rises, the initial rate rises because collisions between substrate molecules and active sites become more frequent. At high concentration all active sites are occupied (saturated), so the rate levels off at its maximum. The enzyme concentration is then the limiting factor.
If more enzyme is added at this stage, there are more active sites and the rate rises again.
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Enzymes
- Catalase is an enzyme found inside liver cells. It breaks down hydrogen peroxide, a toxic by-product of metabolism, into water and oxygen. Hydrogen peroxide breaks down very slowly if no enzyme is present.Describe how catalase lowers the activation energy of the breakdown of hydrogen peroxide.2 marks
- Trypsin is a digestive enzyme made by cells of the pancreas and released into the small intestine, where it hydrolyses proteins in food. Pancreatic cells also contain many enzymes that catalyse reactions of respiration, which provides the cell with ATP.Suggest why enzymes that digest food, such as trypsin, are extracellular.2 marks
- A student investigates the effect of enzyme concentration on the rate at which catalase breaks down hydrogen peroxide. She adds 1.0 cm³ of catalase solution to 10 cm³ of hydrogen peroxide solution, which is in excess, in a buffer at 25 °C, and collects the oxygen produced in a gas syringe. With a catalase solution of concentration X she collects 9 cm³ of oxygen in the first 30 seconds. With a catalase solution of concentration 2X she collects 18 cm³ of oxygen in the first 30 seconds.Calculate the mean rate of oxygen production over the first 30 seconds for each concentration of catalase, and state what the results show about the effect of enzyme concentration on rate.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).