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Transport across membranesEdexcel A-Level Biology A: Revision notes

Section 1

Osmosis

Osmosis is the net movement of free water molecules from a region of higher concentration of free water molecules (a dilute solution) to a region of lower concentration of free water molecules (a more concentrated solution) through a partially permeable membrane.

Solutes bind some water molecules, so a solution with more solute has fewer free water molecules. Water molecules cross in both directions, but there is a net movement down the concentration gradient.

  • Animal cell in pure water: net movement of water in, cell swells and bursts (no cell wall).
  • Animal cell in a concentrated solution: net movement of water out, cell shrinks.
  • Same concentration: no net movement.
Key termsosmosisfree water moleculespartially permeable membrane
Common mistake

Say 'net movement'. Water moves in both directions, so writing that water only moves one way loses the mark.

Section 2

Diffusion and facilitated diffusion

Diffusion is the net movement of particles from a region of higher concentration to lower concentration. It is passive: it does not need ATP.

  • Simple diffusion through the bilayer: small, non-polar molecules such as oxygen and carbon dioxide.
  • Facilitated diffusion through channel proteins (water-filled pores) or carrier proteins (which change shape): for ions and polar molecules such as glucose. It is still passive and goes down the concentration gradient.

The rate of facilitated diffusion levels off at high concentration because all the protein molecules are in use (saturated).

Key termsdiffusionfacilitated diffusionpassive

Section 3

Active transport

Active transport moves substances against their concentration gradient, from low to high concentration, using carrier proteins and energy from ATP.

  1. The molecule binds to a carrier protein.
  2. ATP is hydrolysed, releasing energy (ATP is the immediate source of energy).
  3. The carrier protein changes shape and releases the molecule on the other side.

Active transport stops if respiration is inhibited, which is evidence that it needs ATP. Examples include the uptake of mineral ions by root hair cells and the pumping of sodium ions out of cells.

Key termsactive transportATPcarrier protein
Exam tip

To identify active transport from data, look for movement against a gradient and a requirement for ATP (stops with a respiratory inhibitor).

Section 4

Endocytosis and exocytosis

Large molecules and particles cross membranes in vesicles, using energy from ATP.

  • Endocytosis: the cell surface membrane folds inwards around the material and pinches off as a vesicle inside the cell, as when a phagocyte engulfs a bacterium.
  • Exocytosis: vesicles (for example from the Golgi apparatus) move to the cell surface membrane, fuse with it and release their contents outside, as when insulin is secreted.

Endocytosis removes membrane from the cell surface and exocytosis adds it back.

Key termsendocytosisexocytosisvesicle

Section 5

Comparing the methods

  • Simple diffusion: down the gradient, no ATP, no protein.
  • Facilitated diffusion: down the gradient, no ATP, channel or carrier proteins.
  • Osmosis: down the gradient of free water molecules, no ATP, partially permeable membrane.
  • Active transport: against the gradient, needs ATP, carrier proteins.
  • Endocytosis and exocytosis: bulk transport in vesicles, needs ATP.

Proteins are involved in facilitated diffusion and active transport, so the rate of these can be limited by the number of protein molecules (saturation).

Key termssaturation

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Transport across membranes

  1. Human red blood cells contain a mixture of dissolved solutes with the same overall concentration of free water molecules as a 0.9% sodium chloride solution. A technician places samples of red blood cells in pure water, in 0.9% sodium chloride solution and in 3.0% sodium chloride solution, and observes them under a microscope.
    Explain why the red blood cells in pure water swell and burst.2 marks
  2. A root hair cell contains nitrate ions at a concentration of 40 mmol dm⁻³. The nitrate concentration in the surrounding soil water is 5 mmol dm⁻³. When a student adds a respiratory inhibitor to the solution around the roots, the uptake of nitrate ions falls to almost zero.
    Use the information to explain why the student can conclude that nitrate ions are taken up by active transport.2 marks
  3. Researchers investigated the uptake of three substances, X, Y and Z, by a type of cell. For X and Y, the rate of uptake was measured at external concentrations of 0, 2, 4, 6, 8 and 10 mmol dm⁻³. The rates of uptake of X were 0, 3, 6, 9, 12 and 15 arbitrary units. The rates of uptake of Y were 0, 8, 14, 18, 19 and 19 arbitrary units. Adding a respiratory inhibitor did not change the uptake of X or Y. Substance Z, however, was found inside the cells at a higher concentration than outside, and its uptake stopped when the respiratory inhibitor was added.
    Describe how the rates of uptake of X and Y change as the external concentration increases, and explain the pattern for Y.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).