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The genetic code and protein synthesisEdexcel A-Level Biology A: Revision notes

Section 1

Genes and the genetic code

A gene is a sequence of bases on a DNA molecule that codes for a sequence of amino acids in a polypeptide chain.

The genetic code is how the base sequence is turned into amino acids. It is:

  • a triplet code: three bases, called a codon on mRNA, code for one amino acid
  • non-overlapping: each base belongs to only one codon
  • degenerate: most amino acids are coded for by more than one triplet

Four bases in groups of three give 4³ = 64 possible triplets, enough for 20 amino acids, which explains the degeneracy. Some triplets are start or stop signals.

Key termsgenegenetic codecodontriplet codedegeneratenon-overlapping
Common mistake

Degenerate does not mean one codon codes for several amino acids. It means several codons can code for one amino acid.

Section 2

Types of RNA and key terms

Messenger RNA (mRNA) is a copy of a gene, made in the nucleus and taken to a ribosome. Transfer RNA (tRNA) is a folded molecule with an anticodon at one end and a specific amino acid at the other. Ribosomes are where translation happens.

The template (antisense) strand of DNA is the strand that is copied, so mRNA is complementary to it. The other strand, the coding (sense) strand, has the same base sequence as the mRNA (except T instead of U).

The start codon is AUG, which codes for methionine. The stop codons (UAA, UAG, UGA) do not code for amino acids.

Key termsmRNAtRNAanticodontemplate strandstart codonstop codon

Section 3

Transcription

Transcription makes mRNA from a gene in the nucleus.

  1. RNA polymerase binds to the DNA at the start of the gene and breaks the hydrogen bonds, unwinding a short section.
  2. Free RNA nucleotides pair with the exposed bases of the template strand by complementary base pairing (A with U, T with A, C with G).
  3. RNA polymerase joins the nucleotides by phosphodiester bonds, forming mRNA.
  4. The mRNA leaves through a nuclear pore.

Worked example: template TAC CGA GGT ATT gives mRNA AUG GCU CCA UAA.

Key termstranscriptionRNA polymerasenuclear pore
Exam tip

Pair the template, not the coding strand. A template T gives A in the mRNA, and a template A gives U.

Section 4

Translation

Translation builds the polypeptide at a ribosome in the cytoplasm.

  1. mRNA binds to a ribosome, and translation begins at the start codon, AUG.
  2. A tRNA carrying a specific amino acid has an anticodon that pairs with the codon by complementary base pairing.
  3. A second tRNA binds to the next codon, and a peptide bond forms between the two amino acids (a condensation reaction).
  4. The ribosome moves along the mRNA, adding amino acids, until a stop codon is reached.
  5. No tRNA matches a stop codon, so the polypeptide is released.

The order of codons on the mRNA decides the order of amino acids, which is the primary structure.

Key termstranslationribosomepeptide bond
Common mistake

Do not say tRNA reads the DNA. The anticodon of tRNA pairs with the codon on mRNA.

Section 5

Putting it together

The flow of information is DNA → mRNA → polypeptide.

  • DNA triplets on the template strand give mRNA codons, which give tRNA anticodons matching the template triplets.
  • Each stage uses complementary base pairing.
  • A polypeptide of n amino acids needs at least 3n nucleotides in mRNA, plus 3 for the stop codon.

Worked example: a polypeptide of 18 amino acids needs 18 × 3 + 3 = 57 nucleotides in its mRNA.

Key termsDNA → mRNA → polypeptide

That's the notes covered.

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Exam questions on The genetic code and protein synthesis

  1. The base sequence of a short section of the template (antisense) strand of a gene is TACCGAGGTATT. This section is transcribed to make mRNA that begins with a start codon and ends with a stop codon.
    The codons GCU and GCC both code for the amino acid alanine. State the term used to describe this property of the genetic code and explain what it means.2 marks
  2. During translation in a pancreatic cell, a ribosome moves along an mRNA molecule with the base sequence AUG UUC GGA CAU UGA. The codon UGA is a stop codon.
    Explain how tRNA molecules make sure that the correct amino acid is added at each codon of the mRNA.2 marks
  3. RNA polymerase transcribes a gene in the nucleus of a cell. A section of the DNA template (antisense) strand has the base sequence TACCAGTTCACT.
    Deduce the base sequence of the mRNA transcribed from this section, and describe the role of RNA polymerase in forming it.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).