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2.5 Modelling with functionsIB Maths: Applications and Interpretation HL: Revision notes

Section 1

Linear and piecewise linear models

A linear model f(x)=mx+cf(x)=mx+c has a constant rate of change: the gradient mm is the change in ff per unit of xx, and cc is the value when x=0x=0 (the yy-intercept). It links to the equation of a straight line (SL 2.1) and to an arithmetic sequence, whose terms increase by a constant common difference. A piecewise linear model uses a different line on different parts of the domain, for example mobile phone charges, the depth of a swimming pool or the horizontal distance of an object to a wall. Example: a taxi charges 12 AED for the first 2 km, then 2.50 AED per km. F(x)=12F(x)=12 for 0≤x≤20\leq x\leq2 and F(x)=12+2.5(x−2)F(x)=12+2.5(x-2) for x>2x>2. For a 10 km journey, F(10)=12+2.5(8)=32F(10)=12+2.5(8)=32 AED.

Key termslinear modelgradientpiecewise
Common mistake

Writing 12+2.5x12+2.5x for the whole journey. The 2.50 AED only applies to the distance beyond the first 2 km, so use (x−2)(x-2).

Exam tip

Always interpret the gradient and intercept in context, with units.

Section 2

Quadratic models

A quadratic model is f(x)=ax2+bx+cf(x)=ax^2+bx+c, a≠0a\neq0. Its graph is a parabola with:

  • the yy-intercept (0,c)(0,c)
  • the axis of symmetry x=−b2ax=-\frac{b}{2a}
  • the vertex on that axis, a maximum if a<0a<0 and a minimum if a>0a>0
  • zeros (roots) where f(x)=0f(x)=0, which you can find with your GDC. Example: profit P(x)=−2x2+24x−54P(x)=-2x^2+24x-54 thousand AED from selling xx hundred items. The GDC gives zeros x=3x=3 and x=9x=9, the axis is x=−242(−2)=6x=-\frac{24}{2(-2)}=6 and the maximum profit is P(6)=18P(6)=18 thousand AED. The model breaks even at 300 and 900 items.
Key termsquadratic modelaxis of symmetryvertexzero
Exam tip

The vertex xx-value is exactly halfway between the two zeros, which is a quick check.

Section 3

Exponential models

An exponential model has the form f(x)=kax+cf(x)=ka^x+c (growth if a>1a>1, decay if 0<a<10<a<1; f(x)=ka−x+cf(x)=ka^{-x}+c with a>1a>1 is also decay) or f(x)=kerx+cf(x)=ke^{rx}+c (r>0r>0 growth, r<0r<0 decay). The graph has a horizontal asymptote y=cy=c: it gets closer but never reaches it. Links: compound interest (SL 1.4), geometric sequences (SL 1.3) and amortization (SL 1.7). Example: 2000 AED invested at 4% compound interest gives A(t)=2000(1.04)tA(t)=2000(1.04)^t, so A(10)=2960.49A(10)=2960.49 AED. A cooling drink T=20+60e−0.1tT=20+60e^{-0.1t} has asymptote T=20T=20, the room temperature.

Key termsexponential modelhorizontal asymptotegrowthdecay
Common mistake

Using kk as the asymptote. For f(x)=kax+cf(x)=ka^x+c the asymptote is y=cy=c, and k+ck+c is the initial value.

Section 4

Direct and inverse variation, and cubic models

A power model f(x)=axnf(x)=ax^n with n∈Zn\in\mathbb{Z} describes direct variation when n>0n>0 (for example y=axy=ax or y=ax2y=ax^2, area against radius) and inverse variation when n<0n<0 (for example y=axy=\frac{a}{x}). When n<0n<0 the yy-axis is a vertical asymptote, x=0x=0. Example: nn workers take T=60nT=\frac{60}{n} hours: 4 workers take 15 hours, and doubling the workers halves the time. A cubic model is f(x)=ax3+bx2+cx+df(x)=ax^3+bx^2+cx+d: it has up to 3 zeros and up to 2 turning points, and dd is the yy-intercept. Example: cutting squares of side xx cm from the corners of a 20 cm by 15 cm sheet to make an open box gives V=x(20−2x)(15−2x)=4x3−70x2+300xV=x(20-2x)(15-2x)=4x^3-70x^2+300x. The GDC shows a maximum V=379V=379 cm3^3 at x=2.83x=2.83, with domain 0<x<7.50<x<7.5.

Key termsdirect variationinverse variationvertical asymptotecubic model
Common mistake

Forgetting the domain of a model. A length such as xx cannot be negative, and here 2x2x cannot exceed 15.

Section 5

Sinusoidal models

A sinusoidal model f(x)=asin⁡(bx)+df(x)=a\sin(bx)+d or f(x)=acos⁡(bx)+df(x)=a\cos(bx)+d repeats regularly. At SL you only need to find or predict:

  • the amplitude ∣a∣|a| (half the distance between the maximum and minimum)
  • the period 360∘b\frac{360^\circ}{b}
  • the principal axis y=dy=d, midway between the maximum d+ad+a and the minimum d−ad-a. You do not need to convert between sin⁡x\sin x and cos⁡x\cos x. Example: T(t)=6sin⁡(15t∘)+24T(t)=6\sin(15t^\circ)+24 models temperature tt hours after 06:00. The amplitude is 6, the period is 36015=24\frac{360}{15}=24 hours, the axis is T=24T=24, the maximum is 30 °C and the minimum is 18 °C.
Key termssinusoidal modelamplitudeperiodprincipal axis
Exam tip

Set your GDC to degree mode for sin⁡(bx∘)\sin(bx^\circ) unless the question uses radians.

Section 6

Choosing a model

Choose the model from the shape and the context:

  • constant rate of change: linear
  • one turning point, symmetric: quadratic
  • multiplying by a constant factor, or levelling off towards an asymptote: exponential
  • decreasing curve with a vertical asymptote at x=0x=0: inverse variation
  • regular repeating pattern: sinusoidal. Always state the domain that makes sense, and answer in context with units, giving 3 significant figures (money to 2 d.p.).
Key termsdomaincontext

That's the notes covered.

Carry on to the next subtopic.

Exam questions on 2.5 Modelling with functions

  1. A mobile phone plan costs 45 AED per month and includes 5 GB of data. Each extra GB used beyond 5 GB costs 8 AED. The monthly cost is CC AED when dd GB are used, d≥0d\geq 0.
    Write down the gradient of the model for d>5d>5 and interpret it in context.2 marks
  2. A footballer kicks a ball from the ground. Its height hh metres, when it has travelled a horizontal distance xx metres, is modelled by h(x)=−0.04x2+0.96xh(x)=-0.04x^2+0.96x, for x≥0x\geq 0 while the ball is in the air.
    Use your GDC to find the horizontal distance at which the ball is at a height of 5 m on its way up.2 marks
  3. A cup of coffee is poured at t=0t=0 minutes in a room. Its temperature TT °C is modelled by T(t)=22+68e−0.05tT(t)=22+68e^{-0.05t}, for t≥0t\geq 0.
    (i) Find the temperature of the coffee when it is poured. (ii) Write down the equation of the horizontal asymptote of the graph of TT and interpret it in context.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).