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2.8 Transformations of graphsIB Maths: Applications and Interpretation HL: Revision notes

Section 1

Translations

A translation slides the whole graph without turning or resizing it.

  • y=f(x)+by=f(x)+b moves the graph bb units up (down if b<0b<0).
  • y=f(x−a)y=f(x-a) moves the graph aa units to the right (left if a<0a<0). The translation by the vector (3−2)\begin{pmatrix}3\\ -2\end{pmatrix} is 3 units right and 2 units down, giving y=f(x−3)−2y=f(x-3)-2. Each point (x,y)(x,y) moves to (x+3,y−2)(x+3,y-2). Example: f(x)=x2f(x)=x^2 translated by (3−2)\begin{pmatrix}3\\ -2\end{pmatrix} gives y=(x−3)2−2y=(x-3)^2-2, with vertex (3,−2)(3,-2).
Key termstranslationvector
Common mistake

Moving the wrong way for f(x−a)f(x-a). The sign inside the brackets is the opposite of the direction: f(x−3)f(x-3) moves the graph 3 units to the right.

Section 2

Reflections

  • y=−f(x)y=-f(x) is a reflection in the xx-axis: every yy-coordinate changes sign, so (x,y)→(x,−y)(x,y)\to(x,-y).
  • y=f(−x)y=f(-x) is a reflection in the yy-axis: every xx-coordinate changes sign, so (x,y)→(−x,y)(x,y)\to(-x,y). Example: if P(4,6)P(4,6) lies on y=f(x)y=f(x), then (4,−6)(4,-6) lies on y=−f(x)y=-f(x) and (−4,6)(-4,6) lies on y=f(−x)y=f(-x). Points on the line of reflection do not move.
Key termsreflection
Common mistake

Mixing up the two reflections. A minus sign outside ff changes the yy-values; a minus sign inside changes the xx-values.

Section 3

Stretches and invariant axes

  • y=p f(x)y=p\,f(x) is a vertical stretch with scale factor pp (parallel to the yy-axis): each yy-coordinate is multiplied by pp.
  • y=f(qx)y=f(qx) is a horizontal stretch with scale factor 1q\frac1q (parallel to the xx-axis): each xx-coordinate is divided by qq. Points on the xx-axis are invariant (do not move) under a vertical stretch, and points on the yy-axis are invariant under a horizontal stretch. Example: y=sin⁡xy=\sin x to y=4sin⁡2xy=4\sin 2x is a vertical stretch with scale factor 4 and a horizontal stretch with scale factor 12\frac12. The amplitude becomes 4 and the period becomes 2π2=π\frac{2\pi}{2}=\pi. Under y=f(3x)y=f(3x) the point (4,6)(4,6) moves to (43,6)\left(\frac43,6\right).
Key termsstretchscale factorinvariant
Common mistake

Using scale factor qq for y=f(qx)y=f(qx). The horizontal scale factor is 1q\frac1q: y=f(2x)y=f(2x) squashes the graph to half its width.

Section 4

Composite transformations and order

A composite transformation is two or more transformations applied one after another. The order can change the result. Example: y=x2y=x^2 to y=3x2+2y=3x^2+2 is a vertical stretch with scale factor 3 followed by a translation by (02)\begin{pmatrix}0\\ 2\end{pmatrix}. Doing the translation first gives 3(x2+2)=3x2+63(x^2+2)=3x^2+6, a different graph. Another example: y=sin⁡xy=\sin x to y=4sin⁡2x+1y=4\sin 2x+1 uses two stretches (any order) and then a translation up 1. To find the equation, build it up in the order described: after each step, write the new equation and use it as the starting point for the next. Two transformations in different directions (for example a horizontal translation and a vertical stretch) can be applied in either order; two in the same direction cannot.

Key termscomposite transformationorder
Exam tip

When you describe a composite transformation, say each step fully: the type, the scale factor or vector, and the direction.

Section 5

Transformations in context

Transformations let you adapt a known model. In g(t)=f(t−2)g(t)=f(t-2), the graph of ff is moved 2 units to the right, so every value of ff happens 2 hours (or weeks) later. In y=f(x)+by=f(x)+b, every value rises by bb. A vertical stretch y=pf(x)y=pf(x) scales every output, for example doubling the population at every time. Worked example: if f(t)=2tf(t)=2^t then 3f(t−2)=3×2t−2=34×2t3f(t-2)=3\times2^{t-2}=\frac34\times2^t, so shifting right by 2 and stretching by 3 is the same as a single vertical stretch with scale factor 34\frac34. Check by substituting a point: if (1,5)(1,5) is on y=f(x)y=f(x) and the translation is (3−2)\begin{pmatrix}3\\ -2\end{pmatrix}, then (4,3)(4,3) should be on the new graph.

Exam tip

Test your answer on one point from the original graph. If the image does not land on the new equation, the transformation is wrong.

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Exam questions on 2.8 Transformations of graphs

  1. The graph of y=f(x)y=f(x), where f(x)=x2+4f(x)=x^2+4, is translated by the vector (3−2)\begin{pmatrix}3\\ -2\end{pmatrix} to give the graph of y=g(x)y=g(x).
    Find g(x)g(x) in the form ax2+bx+cax^2+bx+c.2 marks
  2. The point P(4,6)P(4,6) lies on the graph of y=f(x)y=f(x).
    The graph of y=f(x)y=f(x) is stretched vertically with scale factor 3 and the resulting graph is then reflected in the xx-axis. Write down the equation of the final graph and the coordinates of the image of PP.2 marks
  3. The graph of y=sin⁡xy=\sin x (xx in radians) is transformed to give the graph of y=g(x)y=g(x), where g(x)=4sin⁡2x+1g(x)=4\sin 2x+1.
    Describe fully a sequence of three transformations that maps the graph of y=sin⁡xy=\sin x onto the graph of y=g(x)y=g(x).3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).