All revision notes topics

4.3 Measures of central tendency and dispersionIB Maths: Applications and Interpretation HL: Revision notes

Section 1

Mean, median and mode

The mean is xˉ=∑xn\bar{x}=\frac{\sum x}{n}. The median is the middle value of the ordered data (the mean of the two middle values if nn is even). The mode is the most frequent value. Example: 2,0,3,1,4,1,2,5,1,12,0,3,1,4,1,2,5,1,1 ordered is 0,1,1,1,1,2,2,3,4,50,1,1,1,1,2,2,3,4,5: mean =2010=2=\frac{20}{10}=2, median =1+22=1.5=\frac{1+2}{2}=1.5, mode =1=1. For a frequency table, xˉ=∑fx∑f\bar{x}=\frac{\sum fx}{\sum f}, which your GDC can do from lists.

Key termsmeanmedianmode
Exam tip

The median is not affected by extreme values, so it suits skewed data or data with outliers; the mean uses every value.

Section 2

Grouped data and the modal class

For grouped data the individual values are unknown, so use the mid-interval value of each class (the mean of its end points) to estimate the mean: xˉ≈∑f m∑f.\bar{x}\approx\frac{\sum f\,m}{\sum f}. The modal class is the class with the greatest frequency, for equal class widths only. Example: classes 0≤t<10,…,40≤t<500\le t<10,\dots,40\le t<50 with frequencies 6,14,18,9,36,14,18,9,3. Mid-interval values 5,15,25,35,455,15,25,35,45 give ∑fm=1140\sum fm=1140 and xˉ≈114050=22.8\bar{x}\approx\frac{1140}{50}=22.8. Modal class: 20≤t<3020\le t<30.

Key termsmid-interval valuemodal class
Common mistake

Dividing ∑fm\sum fm by the number of classes. Divide by the total frequency ∑f\sum f.

Common mistake

Using the frequency instead of the mid-interval value, or the class end points instead of the midpoints.

Section 3

Measures of dispersion

Range =max−min=\text{max}-\text{min}. Interquartile range IQR=Q3−Q1\text{IQR}=Q_3-Q_1 measures the spread of the middle half and is not affected by outliers. The standard deviation σ\sigma measures typical distance from the mean; the variance is its square, σ2\sigma^2. Use your GDC (one-variable statistics) to find σ\sigma. At SL the data set is treated as the population unless stated otherwise, so use the population standard deviation σx\sigma_x; a sample version sn−1s_{n-1} gives a slightly larger value. Hand calculation, σ=∑(x−xˉ)2n\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{n}}, can help understanding but is not required. Example: for 0,1,1,1,1,2,2,3,4,50,1,1,1,1,2,2,3,4,5, ∑(x−2)2=22\sum(x-2)^2=22, so variance =2.2=2.2 and σ=1.48\sigma=1.48.

Key termsstandard deviationvariancerangeinterquartile range
Common mistake

Quoting the sample standard deviation from the GDC when the question says the data are the whole population (or the opposite).

Section 4

Quartiles from technology

Quartiles divide ordered data into four equal parts: Q1Q_1 (lower quartile), the median Q2Q_2 and Q3Q_3 (upper quartile). For discrete data, find them with your GDC. There are different methods for quartiles (for example whether the median is included in each half when nn is odd), so a value from your GDC may differ slightly from a hand calculation. Use the GDC value. Example: 10.8,11.0,11.0,11.2,11.2,11.4∣11.4,11.6,11.6,11.8,12.0,12.010.8,11.0,11.0,11.2,11.2,11.4\mid11.4,11.6,11.6,11.8,12.0,12.0 gives Q1=11.1Q_1=11.1, Q3=11.7Q_3=11.7, IQR=0.6\text{IQR}=0.6.

Key termsquartile

Section 5

Effect of constant changes

If every data item has a constant kk added or subtracted, the mean, median and quartiles change by kk, but the standard deviation, variance, IQR and range are unchanged. If every item is multiplied by kk, the mean, median, quartiles, standard deviation, IQR and range are all multiplied by kk, and the variance by k2k^2. Example: temperatures with mean 3030 and σ=4\sigma=4, converted by F=1.8C+32F=1.8C+32: new mean =1.8(30)+32=86=1.8(30)+32=86; new σ=1.8×4=7.2\sigma=1.8\times4=7.2 (the +32+32 does not change spread); new variance =7.22=51.84=7.2^2=51.84.

Key termsconstant changescaling
Common mistake

Adding the constant to the standard deviation. Shifting every value leaves the spread unchanged.

Exam tip

Variance scales by k2k^2 because variance is the square of standard deviation.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on 4.3 Measures of central tendency and dispersion

  1. A hockey team scores the following numbers of goals in 10 matches: 2, 0, 3, 1, 4, 1, 2, 5, 1, 1. Treat these 10 matches as the whole population.
    Use your GDC to find the standard deviation and the variance of the number of goals.2 marks
  2. The waiting times, tt minutes, of 50 patients at a clinic are recorded. 0≤t<100\le t<10: 6 patients; 10≤t<2010\le t<20: 14 patients; 20≤t<3020\le t<30: 18 patients; 30≤t<4030\le t<40: 9 patients; 40≤t<5040\le t<50: 3 patients.
    Estimate the mean waiting time.2 marks
  3. The daily maximum temperature in a town over a month has mean 30 ∘30\,^\circC and standard deviation 4 ∘4\,^\circC. A visitor converts each temperature to degrees Fahrenheit using F=1.8C+32F=1.8C+32.
    Find the mean temperature in degrees Fahrenheit, and write down the variance of the temperatures in degrees Celsius.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).