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1.2 Arithmetic sequences and seriesIB Maths: Applications and Interpretation HL: Revision notes

Section 1

Arithmetic sequences

In an arithmetic sequence each term is found by adding a fixed number, the common difference dd, to the previous term: un+1=un+du_{n+1}=u_n+d. The nnth term is un=u1+(n−1)d.u_n=u_1+(n-1)d. Example: 7,11,15,…7,11,15,\ldots has u1=7u_1=7 and d=4d=4, so u20=7+19×4=83u_{20}=7+19\times4=83. To find which term equals 135, solve 7+4(n−1)=1357+4(n-1)=135, giving n=33n=33. Given two terms, subtract: u8−u3=5du_8-u_3=5d. If u3=11u_3=11 and u8=31u_8=31 then d=4d=4 and u1=11−2(4)=3u_1=11-2(4)=3.

Key termsarithmetic sequencecommon difference
Common mistake

Using u1+ndu_1+nd. The number of steps from the first term to the nnth term is n−1n-1.

Section 2

Sum of an arithmetic series

The sum of the first nn terms is Sn=n2(2u1+(n−1)d)=n2(u1+un).S_n=\frac n2\left(2u_1+(n-1)d\right)=\frac n2\left(u_1+u_n\right). Example: for u1=7u_1=7, d=4d=4 and n=20n=20, S20=202(7+83)=900S_{20}=\frac{20}{2}\left(7+83\right)=900. If you know the sum and need nn, form an equation in nn and solve it on your GDC. Reject a negative or non-integer value of nn.

Key termsseries
Common mistake

Forgetting the factor n2\frac n2, or using u1u_1 instead of 2u12u_1 in the first form of the formula.

Section 3

Sigma notation

∑k=1nuk\sum_{k=1}^{n}u_k means u1+u2+⋯+unu_1+u_2+\cdots+u_n: the sum of the terms from k=1k=1 up to k=nk=n. Example: ∑k=112(3k+2)\sum_{k=1}^{12}(3k+2) is an arithmetic series with u1=5u_1=5, u12=38u_{12}=38 and 12 terms, so its sum is 122(5+38)=258\frac{12}{2}(5+38)=258. The number of terms in ∑k=ab\sum_{k=a}^{b} is b−a+1b-a+1.

Key termssigma notation

Section 4

Technology

A spreadsheet or GDC can list the terms of a sequence and their sums. Type the first term, then a rule such as 'previous term + dd', and fill down. If you use technology in an exam you must still identify the first term u1u_1 and the common difference dd and show them in your working. Your GDC can also solve equations such as n2(2u1+(n−1)d)=1275\frac n2(2u_1+(n-1)d)=1275 or find the first nn for which a term or sum passes a target. Check the answer in context.

Exam tip

Write u1=…u_1=\ldots and d=…d=\ldots before using the GDC. Marks are given for identifying them.

Section 5

Applications and modelling

Simple interest gives an arithmetic sequence: the interest each year is the same fixed amount. For 2500 EUR at 4% simple interest per year, the value after tt years is 2500+100t2500+100t, so after 6 years it is 3100 EUR. Real data are rarely perfectly arithmetic. Estimate dd from the data, for example d≈u5−u14d\approx\frac{u_5-u_1}{4}, and build a model un=u1+(n−1)du_n=u_1+(n-1)d. Use the model to predict, and always comment on reliability: extrapolating far beyond the data is risky because the real trend may change.

Key termssimple interestextrapolation

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Exam questions on 1.2 Arithmetic sequences and series

  1. An arithmetic sequence has first term u1=7u_1=7 and common difference d=4d=4.
    Find the value of nn for which un=135u_n=135.2 marks
  2. A cyclist trains for 20 days. On day 1 she cycles 12 km, and on each following day she cycles 1.5 km further than on the previous day.
    Find the first day on which she cycles more than 30 km.2 marks
  3. An arithmetic sequence has u3=11u_3=11 and u8=31u_8=31.
    Find the common difference dd and the first term u1u_1.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).