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Transformations of functionsIB MYP Maths Extended: Revision notes

Section 1

Translations: f(x)+af(x)+a and f(x+a)f(x+a)

Adding aa outside the function, y=f(x)+ay=f(x)+a, translates the graph up by aa (down if aa is negative). Every yy-coordinate changes; the xx-coordinates stay. Adding aa inside, y=f(x+a)y=f(x+a), translates the graph left by aa (right if aa is negative). Every xx-coordinate changes by −a-a. Example: if ff has a minimum at (2,−1)(2,-1), then f(x)+3f(x)+3 has its minimum at (2,2)(2,2) and f(x−4)f(x-4) has its minimum at (6,−1)(6,-1).

Key termstranslationimage
Common mistake

Moving f(x+3)f(x+3) to the right. Changes inside the brackets work in the opposite direction to what you expect.

Section 2

Reflections: −f(x)-f(x)

y=−f(x)y=-f(x) reflects the graph in the xx-axis: each yy-coordinate changes sign, so (4,6)(4,6) becomes (4,−6)(4,-6), and a minimum becomes a maximum. y=f(−x)y=f(-x) (the case k=−1k=-1 in f(kx)f(kx)) reflects the graph in the yy-axis: each xx-coordinate changes sign.

Key termsreflection

Section 3

Stretches: kf(x)kf(x) and f(kx)f(kx)

y=kf(x)y=kf(x) is a vertical stretch, scale factor kk, from the xx-axis: every yy-coordinate is multiplied by kk. So (4,6)(4,6) on y=f(x)y=f(x) becomes (4,12)(4,12) on y=2f(x)y=2f(x). y=f(kx)y=f(kx) is a horizontal stretch, scale factor 1k\frac1k, from the yy-axis: every xx-coordinate is divided by kk. So (4,6)(4,6) becomes (2,6)(2,6) on y=f(2x)y=f(2x), and f(x2)f\left(\frac{x}{2}\right) stretches horizontally by factor 22. Points on the axis you stretch from do not move.

Key termsstretchscale factor
Exam tip

For a horizontal change, do the opposite to the number in the brackets: f(x+2)f(x+2) moves left by 22 and f(3x)f(3x) squashes by 13\frac13.

Section 4

Combining transformations and describing them

Apply the transformations to key points one at a time. For y=−f(x+1)y=-f(x+1): the translation first, (4,6)→(3,6)(4,6)\to(3,6), then the reflection, (3,6)→(3,−6)(3,6)\to(3,-6). To describe a transformation, name its type (translation, reflection, stretch) and give the details: the vector, the axis of reflection, or the scale factor and direction. Compare y=x2y=x^2 and y=(x+3)2−5y=(x+3)^2-5: a translation with vector (−3−5)\begin{pmatrix} -3 \\ -5 \end{pmatrix}, so the vertex moves from (0,0)(0,0) to (−3,−5)(-3,-5).

Key termsvector

Section 5

Sketching transformed graphs and using them

To sketch a transformed graph, mark the key points of the original (intercepts, turning points, end points), move each according to the rule, and join them with the same shape. In context, a transformation changes the model: y=f(x)+4y=f(x)+4 lifts a bridge arch 44 m, 1.5f(x)1.5f(x) makes it 1.51.5 times as tall, f(x2)f(\frac x2) makes it twice as wide. Check the new equation against known points such as the ground or the piers.

Key termskey points
Common mistake

Forgetting to move the points that do not lie on an axis. Every point on the graph moves, not just the turning point.

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Exam questions on Transformations of functions

  1. The graph of y=f(x)y=f(x) has a minimum point at (2,−1)(2,-1).
    Write down the coordinates of the turning point of y=−f(x)y=-f(x), and state whether it is a maximum or a minimum.2 marks
  2. The point (4,6)(4,6) lies on the graph of y=f(x)y=f(x).
    Find the coordinates of the image of (4,6)(4,6) on the graph of y=−f(x+1)y=-f(x+1).2 marks
  3. The graph of y=x2y=x^2 is transformed to give the graph of y=(x+3)2−5y=(x+3)^2-5.
    Describe the single transformation, and write down the coordinates of the vertex of the new graph.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).