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Vectors and translation vectorsIB MYP Maths Extended: Revision notes

Section 1

Column vectors

A vector has a size and a direction. In two dimensions we write it as a column vector (xy)\begin{pmatrix}x\\ y\end{pmatrix}: xx units across (right is positive) and yy units up (up is positive). The vector from point AA to point BB is written AB→\overrightarrow{AB}, and AB→=B−A.\overrightarrow{AB}=B-A. For A(1,1)A(1,1) and B(6,2)B(6,2): AB→=(51)\overrightarrow{AB}=\begin{pmatrix}5\\ 1\end{pmatrix}. Vectors with the same components are equal, wherever they are drawn. The vector BA→\overrightarrow{BA} goes the opposite way, so BA→=−AB→=(−5−1)\overrightarrow{BA}=-\overrightarrow{AB}=\begin{pmatrix}-5\\ -1\end{pmatrix}. In print a vector may be written in bold, such as a\mathbf a.

Key termsvectorcolumn vectorcomponent
Common mistake

Finding AB→\overrightarrow{AB} as A−BA-B. It is the end point minus the start point: B−AB-A.

Section 2

Adding, subtracting and multiplying by a scalar

Work on each component separately.

  • Add: (ab)+(cd)=(a+cb+d)\begin{pmatrix}a\\ b\end{pmatrix}+\begin{pmatrix}c\\ d\end{pmatrix}=\begin{pmatrix}a+c\\ b+d\end{pmatrix}.
  • Subtract: (ab)−(cd)=(a−cb−d)\begin{pmatrix}a\\ b\end{pmatrix}-\begin{pmatrix}c\\ d\end{pmatrix}=\begin{pmatrix}a-c\\ b-d\end{pmatrix}.
  • Multiply by a number (scalar) kk: k(ab)=(kakb)k\begin{pmatrix}a\\ b\end{pmatrix}=\begin{pmatrix}ka\\ kb\end{pmatrix}. Worked example. p=(3−2)\mathbf p=\begin{pmatrix}3\\ -2\end{pmatrix} and q=(−14)\mathbf q=\begin{pmatrix}-1\\ 4\end{pmatrix}. Then p+2q=(3−2)+(−28)=(16)\mathbf p+2\mathbf q=\begin{pmatrix}3\\ -2\end{pmatrix}+\begin{pmatrix}-2\\ 8\end{pmatrix}=\begin{pmatrix}1\\ 6\end{pmatrix}. Multiplying by a negative number reverses the direction. Two vectors are parallel if one is a scalar multiple of the other.
Key termsscalarparallel vectors
Common mistake

Multiplying only the top component by the scalar. Multiply both.

Section 3

Magnitude of a vector

The magnitude (length) of (xy)\begin{pmatrix}x\\ y\end{pmatrix} comes from Pythagoras' theorem: ∣(xy)∣=x2+y2.\left|\begin{pmatrix}x\\ y\end{pmatrix}\right|=\sqrt{x^2+y^2}. For p=(3−2)\mathbf p=\begin{pmatrix}3\\ -2\end{pmatrix}, ∣p∣=9+4=13|\mathbf p|=\sqrt{9+4}=\sqrt{13}. The distance between points AA and BB is ∣AB→∣|\overrightarrow{AB}|. Magnitude is never negative, and the sign of a component does not matter because it is squared. Leave answers as surds when the question says exact, or round to 3 significant figures.

Key termsmagnitude
Common mistake

Adding the magnitudes of two vectors to get the magnitude of their sum. Add the vectors first, then find the magnitude.

Section 4

Translations

A translation moves every point of a shape the same distance in the same direction. It is described by a column vector: (3−2)\begin{pmatrix}3\\ -2\end{pmatrix} means 3 right and 2 down. The shape does not turn or change size.

  • Image of a point == object ++ vector. (2,5)(2,5) translated by (3−2)\begin{pmatrix}3\\ -2\end{pmatrix} is (5,3)(5,3).
  • The vector from an object point to its image is image −- object.
  • The reverse translation is −v-\mathbf v.
  • Two translations in a row add: (43)\begin{pmatrix}4\\ 3\end{pmatrix} then (−72)\begin{pmatrix}-7\\ 2\end{pmatrix} is the single translation (−35)\begin{pmatrix}-3\\ 5\end{pmatrix}.
Key termstranslationimage
Exam tip

To get back to the start, use the negative of the vector.

Section 5

Vectors in geometry

Vectors can be added along a path: AC→=AB→+BC→\overrightarrow{AC}=\overrightarrow{AB}+\overrightarrow{BC}. Useful facts:

  • In a parallelogram ABCDABCD, AD→=BC→\overrightarrow{AD}=\overrightarrow{BC} and AB→=DC→\overrightarrow{AB}=\overrightarrow{DC}.
  • The position vector of the midpoint MM of [AB][AB] is OM→=12(OA→+OB→)\overrightarrow{OM}=\frac12(\overrightarrow{OA}+\overrightarrow{OB}).
  • Parallel lines have parallel vectors. Worked example. Parallelogram ABCDABCD with A(1,1)A(1,1), B(6,2)B(6,2), C(9,6)C(9,6). BC→=(34)\overrightarrow{BC}=\begin{pmatrix}3\\ 4\end{pmatrix}, so D=A+(34)=(4,5)D=A+\begin{pmatrix}3\\ 4\end{pmatrix}=(4,5). The diagonal AC→=(85)\overrightarrow{AC}=\begin{pmatrix}8\\ 5\end{pmatrix} has length 89\sqrt{89}.
Key termsposition vectormidpoint
Exam tip

Draw a quick sketch and label each vector with an arrow before you calculate.

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Exam questions on Vectors and translation vectors

  1. The vectors p\mathbf p and q\mathbf q are given by p=(3−2)\mathbf p=\begin{pmatrix}3\\ -2\end{pmatrix} and q=(−14)\mathbf q=\begin{pmatrix}-1\\ 4\end{pmatrix}.
    The point A(2,5)A(2,5) is translated by p\mathbf p and then by q\mathbf q. Find the coordinates of its final image.2 marks
  2. ABCDABCD is a parallelogram, with the vertices in that order, and A(1,1)A(1,1), B(6,2)B(6,2) and C(9,6)C(9,6).
    Find the exact length of the diagonal [AC][AC].2 marks
  3. A drone starts at the point S(2,−1)S(2,-1) on a map grid, where one unit on the grid is 1 km. It makes a translation (43)\begin{pmatrix}4\\ 3\end{pmatrix} and then a translation (−72)\begin{pmatrix}-7\\ 2\end{pmatrix} to reach the point TT.
    Find the coordinates of TT, and write down the single translation that takes SS directly to TT.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).