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Gas exchange surfaces and the lungEdexcel International A Level Biology: Revision notes

Section 1

Why large organisms need exchange surfaces

Cells need oxygen for aerobic respiration and must remove carbon dioxide. Small organisms such as a flatworm have a large surface area to volume ratio and a short diffusion distance, so diffusion across the body surface supplies all their cells.

As organisms get larger, volume increases faster than surface area, so the surface area to volume ratio falls. The distance from the surface to the inner cells also rises, and active animals have a high demand for oxygen. Large animals therefore need a specialised gas exchange surface such as the lungs.

Key termssurface area to volume ratiodiffusion distancegas exchange surface
Exam tip

Always say 'surface area to volume ratio'. 'Large surface area' alone does not explain why a small organism needs no gas exchange system.

Section 2

What makes a good exchange surface

An efficient exchange surface has:

  • a large surface area, to give many places for diffusion
  • a thin surface (often one cell thick), so the diffusion distance is short
  • a steep concentration gradient, maintained by ventilation and blood flow, so net diffusion continues

Diffusion is the net movement of molecules from a region of higher concentration to a region of lower concentration, down a concentration gradient, and needs no energy from the cell.

Key termsconcentration gradientdiffusion

Section 3

Fick's law

Fick's law links the factors above:

rate of diffusion ∝ (surface area × concentration difference) / thickness of the exchange surface

So the rate doubles if the surface area doubles or the concentration difference doubles, and it halves if the thickness doubles.

Use it to explain disease: in emphysema alveolar walls break down, so surface area falls; in fibrosis scarring thickens the alveolar wall, so the diffusion distance rises. Both reduce the rate of oxygen diffusion into the blood.

Key termsFick's law
Common mistake

Do not say thickness is directly proportional to rate. It is inversely proportional: a thicker surface slows diffusion.

Section 4

Adaptations of the mammalian lung

Air passes down the trachea and bronchi to the alveoli, the exchange surface. Their adaptations:

  • millions of alveoli, giving a very large surface area
  • walls of alveoli and capillaries only one cell thick (squamous cells), so the diffusion distance is very short
  • a dense capillary network around each alveolus, giving a large area of blood close to the air
  • a short distance between the air in an alveolus and the blood in a capillary

These adaptations give a large surface area and a short diffusion distance.

Key termsalveoluscapillary network

Section 5

Maintaining the concentration gradient

Ventilation (breathing in and out) replaces the alveolar air, so the oxygen concentration in the alveoli stays high and the carbon dioxide concentration stays low.

The circulation carries oxygenated blood away from the capillaries and brings in blood with a low oxygen concentration and a high carbon dioxide concentration.

Together these keep oxygen diffusing into the blood and carbon dioxide diffusing out, down their concentration gradients. Faster breathing and a faster heart rate during exercise keep the gradients steep.

Key termsventilation
Exam tip

In a 'maintain the gradient' answer, name both processes: breathing replaces the air and blood flow removes the gases.

Must Know

  • Small organisms have a large surface area to volume ratio; large ones need exchange surfaces
  • Good exchange surfaces are large, thin and have a steep concentration gradient
  • Fick's law: rate ∝ surface area × concentration difference / thickness
  • Alveoli: many, one cell thick, dense capillaries, ventilated
  • Breathing and blood flow maintain the gradient

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Gas exchange surfaces and the lung

  1. Flatworms are flat, leaf-shaped animals less than 1 mm thick. They have no lungs or gills and take in oxygen directly across their body surface. A much larger animal, such as a rabbit, is made of the same types of cell but cannot obtain enough oxygen in this way.
    Explain why the flatworm does not need a specialised gas exchange system.2 marks
  2. A patient has a lung disease in which the walls of the alveoli have become thickened by scar tissue. Doctors measure the rate at which oxygen diffuses from the alveoli into the blood and find that it is lower than normal.
    Use Fick's law to explain why the rate of diffusion of oxygen into the blood is reduced in the first patient.2 marks
  3. The wall of each alveolus in a healthy lung is only one cell thick, and each alveolus is surrounded by a dense network of capillaries. Blood entering these capillaries has a low oxygen concentration and a high carbon dioxide concentration, while the air in the alveoli is repeatedly replaced by breathing.
    Describe how the structure of the alveoli and the surrounding capillaries is adapted for rapid gas exchange.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).