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Oxidative phosphorylation and respiratory quotientEdexcel International A Level Biology: Revision notes

Section 1

The electron transport chain

The reduced coenzymes made in glycolysis, the link reaction and the Krebs cycle (reduced NAD and reduced FAD) carry hydrogen to the electron transport chain. This is a series of electron carriers embedded in the inner mitochondrial membrane, which is folded into cristae to give a large surface area.

  1. Reduced NAD and FAD donate hydrogen atoms, which split into protons (H⁺) and electrons; the coenzymes are reoxidised and can be reused.
  2. The electrons pass from carrier to carrier by redox reactions, releasing energy at each step.
  3. At the end of the chain oxygen is the final electron acceptor. It combines with electrons and H⁺ to form water.
Key termselectron transport chaincristaefinal electron acceptor

Section 2

Chemiosmosis and ATP synthase

The energy released as electrons pass along the chain is used to pump H⁺ ions from the matrix into the intermembrane space. This builds up a proton (electrochemical) gradient across the inner membrane.

The inner membrane is impermeable to H⁺. The ions can return to the matrix only through channels in the enzyme ATP synthase. As they flow down their gradient, the energy is used to join ADP and inorganic phosphate to form ATP. This is chemiosmosis.

The whole process is oxidative phosphorylation: the phosphorylation of ADP using energy released by oxidation of reduced coenzymes. It makes most of the ATP in aerobic respiration.

Key termschemiosmosisATP synthaseoxidative phosphorylationproton gradient
Common mistake

The electron transport chain does not make ATP directly. It pumps protons, and ATP synthase makes ATP as the protons flow back.

Section 3

Why oxygen is essential

Oxygen is the final electron acceptor. Without it electrons cannot leave the chain, so the carriers stay reduced and the chain stops. Protons are no longer pumped, so ATP is no longer made by oxidative phosphorylation.

Reduced NAD and FAD are then not reoxidised, so the Krebs cycle and link reaction also stop.

Substances that uncouple respiration, such as molecules that carry H⁺ across the inner membrane, remove the proton gradient. Electron transport and oxygen uptake continue (or increase), but little ATP is made and the energy is released as heat.

Key termsuncoupling

Section 4

Respiratory quotient

The respiratory quotient (RQ) shows which substrate is being respired:

RQ=volume of CO2 producedvolume of O2 consumedRQ = \dfrac{\text{volume of CO}_2\text{ produced}}{\text{volume of O}_2\text{ consumed}} in the same time.

  • Carbohydrate: about 1.0
  • Protein: about 0.9
  • Lipid: about 0.7, because lipids contain proportionally more hydrogen and less oxygen, so more oxygen is needed to oxidise them
  • Anaerobic respiration: RQ above 1, because carbon dioxide is produced with little or no oxygen used

Worked example: 190 cm³ CO₂ and 250 cm³ O₂ per minute gives RQ = 190 ÷ 250 = 0.76, so mainly lipid is being respired.

Key termsrespiratory quotient
Common mistake

RQ is carbon dioxide produced divided by oxygen used, not the other way round.

Section 5

Core Practical 16: the respirometer

A simple respirometer measures oxygen uptake by germinating seeds or small invertebrates.

  • The organisms are in a sealed tube connected to a capillary tube containing a drop of coloured liquid.
  • Potassium hydroxide solution (or soda lime) absorbs the carbon dioxide, so the volume of gas falls only because oxygen is used, and the liquid moves towards the organisms.
  • Volume of oxygen = distance moved × cross-sectional area of the capillary (πr2\pi r^2). Rate = volume ÷ time.
  • A control tube with glass beads or boiled seeds of the same volume allows for changes in temperature and pressure; use a water bath to keep the temperature constant.

To find the RQ, run a second tube without potassium hydroxide. Its movement shows oxygen taken up minus carbon dioxide produced, so carbon dioxide produced = O₂ uptake (with KOH) − movement without KOH.

Worked example: with KOH 24 mm³; without KOH 4.8 mm³. CO₂ = 24 − 4.8 = 19.2 mm³. RQ = 19.2 ÷ 24 = 0.80.

Key termsrespirometerpotassium hydroxide
Exam tip

A control with glass beads or boiled seeds shows any movement is caused by respiration, and not by changes in temperature or pressure.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Oxidative phosphorylation and respiratory quotient

  1. Skeletal muscle cells make most of their ATP in mitochondria by oxidative phosphorylation. Electron micrographs show that the mitochondria of muscle cells have many more cristae than those of cells that are less active.
    Explain why the mitochondria in muscle cells have many cristae.2 marks
  2. A volunteer who had not eaten for three days breathed through a respirometer. The volunteer used 250 cm³ of oxygen and produced 190 cm³ of carbon dioxide each minute at rest.
    Explain why the respiratory quotient for lipids is lower than that for carbohydrates.2 marks
  3. A student investigates the respiration of 5 g of germinating pea seeds at 20 °C in two simple respirometers. In tube A the carbon dioxide is absorbed by potassium hydroxide solution. Tube B has no potassium hydroxide solution. The cross-sectional area of the capillary tube is 0.80 mm². In 10 minutes the coloured liquid in tube A moved 30 mm towards the seeds, and in tube B it moved 6 mm towards the seeds.
    Explain what the movement of the liquid in tube A measures and calculate the rate of this process in mm³ per minute.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).