Biodiversity and its measurementEdexcel International A Level Biology: Revision notes
Section 1
What is biodiversity?
Biodiversity is the variety of living organisms in a habitat, and it can be considered at three levels: the number of different species, the genetic diversity within each species (the variety of alleles in its gene pool) and the variety of habitats and ecosystems.
Over geological time the variety of life has become extensive, but it is now being threatened by human activity. Habitat destruction (for farming, plantations and building), pollution, over-harvesting, climate change and introduced species all reduce the number of species and the genetic diversity within them.
A species that is endemic is found naturally in only one geographical area and nowhere else. Endemic species, such as those on islands and mountains, are very vulnerable: if the habitat is lost, the whole species is lost.
Endemic does not mean rare or endangered. It means restricted to one area. An endemic species can be common there.
Section 2
Species richness
Species richness is the number of different species in a habitat. It is measured by sampling the habitat (for example random quadrats for plants, or pitfall traps for ground invertebrates), identifying every organism and counting the species.
It is simple, but it has a weakness: it ignores abundance. A field with 5 species, one of which makes up 95% of the individuals, has the same richness as a field with 5 species in similar numbers, although the second is clearly more diverse.
Section 3
Genetic diversity and the heterozygosity index
Biodiversity within a species is measured by its genetic diversity. One measure is the heterozygosity index:
heterozygosity index = number of heterozygotes ÷ number of individuals in the population
The value lies between 0 and 1. A high value means many individuals carry two different alleles, so the population has high genetic diversity.
Worked example: a population of 60 lizards contains 15 heterozygotes for a gene. Heterozygosity index = 15 ÷ 60 = 0.25. A mainland population with 82 heterozygotes among 200 lizards has an index of 0.41, so the island population is less genetically diverse.
Small, isolated populations (for example after habitat loss) tend to have a lower heterozygosity index because they have fewer alleles and more inbreeding. Lower diversity gives natural selection less variation to act on.
Always divide by the total number of individuals, not by the number of homozygotes. The answer must be between 0 and 1.
Section 4
Index of diversity
To compare biodiversity in different habitats, use the index of diversity, D, which takes account of both the number of species and their relative abundance:
D = N(N − 1) ÷ Σn(n − 1)
N is the total number of individuals of all species; n is the number of individuals of each species; Σ means 'sum of'.
Worked example: a sample has 3 species with 10, 5 and 1 individuals. N = 16, so N(N − 1) = 16 × 15 = 240. Σn(n − 1) = (10×9) + (5×4) + (1×0) = 110. D = 240 ÷ 110 = 2.2.
A high D means many species with similar numbers of individuals (a diverse habitat). A low D (close to 1) means few species, or one species dominating. Results are only reliable if sampling is random, sufficiently large and repeated, and comparisons need similar sampling effort in each habitat.
Species with n = 1 contribute 0 to Σn(n − 1). Do not leave them out of N, though, because each individual still counts towards the total.
Section 5
Summary for the exam
- Biodiversity can be species richness (habitat) or genetic diversity (within a species).
- Endemic = found in one place only, so highly vulnerable to habitat loss.
- Heterozygosity index = heterozygotes ÷ individuals.
- D = N(N − 1) ÷ Σn(n − 1); higher D = more diverse.
- Evaluate conclusions: sample size, randomness, repeats and other variables.
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Biodiversity and its measurement
- A conservation team surveyed a cloud forest on a tropical mountain. Many of the species they recorded, including a tree frog and an orchid, are found nowhere else in the world.Explain why endemic species are particularly vulnerable to extinction when their habitat is destroyed.2 marks
- Researchers studied one gene with two alleles in lizards. On a small island, a population of 60 lizards contained 15 heterozygotes. On the mainland, a population of 200 lizards of the same species contained 82 heterozygotes.Suggest two reasons why the island population has a lower heterozygosity index than the mainland population.2 marks
- Students estimated the biodiversity of two meadows, A and B, by counting the individuals of each plant species in random quadrats. Meadow A contained 5 species, with 20, 15, 10, 4 and 1 individuals. Meadow B contained 4 species, with 38, 8, 3 and 1 individuals. Meadow B had been treated with a herbicide the previous year, but meadow A had not. The index of diversity is D = N(N − 1) / Σn(n − 1), where N is the total number of individuals of all species and n is the number of individuals of each species.Calculate the index of diversity D for meadow A. Show your working.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).