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Differential equations reducible by substitutionEdexcel International A Level Further Maths: Flashcards

What these 13 flashcards ask

  • What is \frac{dy}{dx} if y=vx?
  • What type of equation is \frac{dy}{dx}=\frac{x^2+y^2}{xy}?
  • Result of y=vx on \frac{dy}{dx}=\frac{x+y}{x}?
  • What is \frac{dz}{dx} if z=x+y?
  • What is \frac{dz}{dx} if z=y-x?
  • What is \frac{dz}{dx} if z=\frac1y?
  • What is \frac{dz}{dx} if z=y^2?
  • Standard integral: \int\frac{1}{1+z^2}\,dz?
  • Last step when using a substitution?
  • After y=vx, how are the variables separated?
  • Why divide by y^2 when z=\frac1y?
  • What should you state for solutions with \ln x or \sqrt{\ \ }?
  • After using z=\frac1y the equation is \frac{dz}{dx}-\frac zx=-1. The integrating factor?

Exam questions on Differential equations reducible by substitution

  1. Consider the differential equation dydx=x+yx\frac{dy}{dx}=\frac{x+y}{x} for x>0x>0, and the substitution y=vxy=vx, where vv is a function of xx.
    Find the general solution, giving yy in terms of xx.2 marks
  2. Consider the differential equation dydx+yx=y2\frac{dy}{dx}+\frac yx=y^2 for x>0x>0, y>0y>0, and the substitution z=1yz=\frac1y.
    The substitution transforms the equation into dzdx−zx=−1\frac{dz}{dx}-\frac zx=-1. Find the general solution for zz in terms of xx.2 marks
  3. Consider the differential equation dydx=(x+y)2\frac{dy}{dx}=(x+y)^2.
    Show that the substitution z=x+yz=x+y transforms the equation into dzdx=1+z2\frac{dz}{dx}=1+z^2.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).