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Focus-directrix properties and eccentricityEdexcel International A Level Further Maths: Flashcards

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State the focus-directrix property.

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State the focus-directrix property.
PS=e×PMPS=e\times PM, with MM the foot of the perpendicular from PP to the directrix.
What value of ee gives an ellipse?
0<e<10<e<1
What value of ee gives a hyperbola?
e>1e>1
Ellipse: relation between aa, bb and ee?
b2=a2(1−e2)b^2=a^2\left(1-e^2\right)
Hyperbola: relation between aa, bb and ee?
b2=a2(e2−1)b^2=a^2\left(e^2-1\right)
Foci of x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 and of x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1?
(±ae,0)(\pm ae,0) in both cases.
Directrices of the ellipse and hyperbola?
x=±aex=\pm\frac ae
Where are the ellipse's foci and directrices compared with aa?
Foci at ae<aae<a (inside); directrices at ae>a\frac ae>a (outside).
Where are the hyperbola's foci and directrices compared with aa?
Foci at ae>aae>a; directrices at ae<a\frac ae<a (between the vertices).
Eccentricity of x225+y216=1\frac{x^2}{25}+\frac{y^2}{16}=1?
35\frac35
Eccentricity of x29−y216=1\frac{x^2}{9}-\frac{y^2}{16}=1?
53\frac53
How do you find aa given foci (±c,0)(\pm c,0) and ee?
ae=cae=c, so a=cea=\frac ce.
How do you turn PS=e×PMPS=e\times PM into an equation?
Square both sides, write PS2PS^2 and PM2PM^2 in xx and yy, and rearrange.
Which focus goes with which directrix?
(ae,0)(ae,0) with x=aex=\frac ae, and (−ae,0)(-ae,0) with x=−aex=-\frac ae.

Exam questions on Focus-directrix properties and eccentricity

  1. The ellipse EE has equation x225+y216=1\frac{x^2}{25}+\frac{y^2}{16}=1.
    Find the equations of the directrices of EE.2 marks
  2. The hyperbola HH has equation x29−y216=1\frac{x^2}{9}-\frac{y^2}{16}=1.
    The point P(5,163)P\left(5,\frac{16}{3}\right) lies on HH. Verify that PS=e×PMPS=e\times PM, where SS is the focus (5,0)(5,0) and MM is the foot of the perpendicular from PP to the corresponding directrix.2 marks
  3. An ellipse EE has its centre at the origin and its foci at (±4,0)(\pm4,0) on the xx-axis. Its eccentricity is 23\frac23.
    Find the equation of EE in the form x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).