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Differentiating hyperbolic functionsEdexcel International A Level Further Maths: Flashcards

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$\frac{d}{dx}\sinh x$?

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ddxsinh⁡x\frac{d}{dx}\sinh x?
cosh⁡x\cosh x
ddxcosh⁡x\frac{d}{dx}\cosh x?
sinh⁡x\sinh x (no minus sign)
ddxtanh⁡x\frac{d}{dx}\tanh x?
sech⁡2x\operatorname{sech}^2x
sech⁡x\operatorname{sech}x in terms of cosh⁡x\cosh x?
sech⁡x=1cosh⁡x\operatorname{sech}x=\frac{1}{\cosh x}
sech⁡2x\operatorname{sech}^2x in terms of tanh⁡x\tanh x?
sech⁡2x=1−tanh⁡2x\operatorname{sech}^2x=1-\tanh^2x
ddxsinh⁡kx\frac{d}{dx}\sinh kx?
kcosh⁡kxk\cosh kx
ddxcosh⁡kx\frac{d}{dx}\cosh kx?
ksinh⁡kxk\sinh kx
ddxtanh⁡3x\frac{d}{dx}\tanh3x?
3sech⁡23x3\operatorname{sech}^23x
ddxsinh⁡2x\frac{d}{dx}\sinh^2x?
2sinh⁡xcosh⁡x=sinh⁡2x2\sinh x\cosh x=\sinh2x
ddx(xsinh⁡2x)\frac{d}{dx}\left(x\sinh^2x\right)?
sinh⁡2x+2xsinh⁡xcosh⁡x\sinh^2x+2x\sinh x\cosh x
Which identity proves the derivative of tanh⁡x\tanh x?
cosh⁡2x−sinh⁡2x=1\cosh^2x-\sinh^2x=1
Solve sinh⁡x=2\sinh x=2 without a calculator function.
Put u=exu=e^x: u2−4u−1=0u^2-4u-1=0, so x=ln⁡(2+5)x=\ln(2+\sqrt5).
Why reject a negative root when solving for exe^x?
ex>0e^x>0 for all real xx.

Exam questions on Differentiating hyperbolic functions

  1. The hyperbolic functions are defined by sinh⁡x=ex−e−x2\sinh x=\frac{e^x-e^{-x}}{2}, cosh⁡x=ex+e−x2\cosh x=\frac{e^x+e^{-x}}{2} and tanh⁡x=sinh⁡xcosh⁡x\tanh x=\frac{\sinh x}{\cosh x}, and sech⁡x=1cosh⁡x\operatorname{sech}x=\frac{1}{\cosh x}.
    Use the quotient rule to show that ddx(tanh⁡x)=sech⁡2x\frac{d}{dx}\left(\tanh x\right)=\operatorname{sech}^2x.2 marks
  2. The curve CC has equation y=xsinh⁡2xy=x\sinh^2x.
    Show that CC has exactly one stationary point.2 marks
  3. The function ff is defined by f(x)=cosh⁡2xx+1f(x)=\frac{\cosh2x}{x+1} for x>−1x>-1.
    Find f′(x)f'(x).3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).