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Hooke's lawEdexcel International A Level Further Maths: Flashcards

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State Hooke's law for an elastic string.

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State Hooke's law for an elastic string.
T=λxlT=\frac{\lambda x}{l}: tension is proportional to extension.
What do TT, λ\lambda, xx and ll stand for?
Tension, modulus of elasticity, extension and natural length.
What are the units of the modulus of elasticity?
Newtons (N).
What is the natural length of a string?
Its length when no force acts on it (slack, with zero tension).
When does an elastic string exert a tension?
Only when its length exceeds its natural length.
What is the extension?
Length of the stretched string minus its natural length.
How does a spring differ from a string?
A spring can be compressed and then exerts a thrust; a string cannot push.
Rearrange Hooke's law to find the extension.
x=Tlλx=\frac{Tl}{\lambda}.
What is the stiffness of a string?
λl\frac{\lambda}{l}, the force per unit extension.
A particle hangs from a string in equilibrium. What is the tension?
T=mgT=mg.
A particle on a smooth plane at angle α\alpha is held by a string along the slope. What is TT?
T=mgsin⁡αT=mg\sin\alpha.
What does 'light' mean for a string?
Its mass is negligible, so the tension is the same throughout.

Exam questions on Hooke's law

  1. A light elastic string has natural length 0.50.5 m and modulus of elasticity 2020 N. One end of the string is fixed to a point AA and a particle PP of mass 0.60.6 kg is attached to the other end. The particle hangs in equilibrium vertically below AA. Take g=9.8g=9.8 m s−2^{-2}.
    The particle is replaced by a particle of mass MM kg, and in equilibrium the string has length 0.70.7 m. Find MM.2 marks
  2. A light spring has natural length 0.50.5 m and modulus of elasticity 14.714.7 N. The spring stands vertically with its lower end fixed to horizontal ground. A particle of mass 0.90.9 kg rests in equilibrium on the top of the spring. Take g=9.8g=9.8 m s−2^{-2}.
    The particle is replaced by a particle of mass MM kg, and in equilibrium the length of the spring is 0.350.35 m. Find MM.2 marks
  3. Two light elastic strings APAP and BPBP have natural lengths 0.60.6 m and 0.50.5 m and moduli of elasticity 2424 N and 3030 N respectively. The ends AA and BB are fixed to points 22 m apart on a smooth horizontal table, and the other ends are joined to a particle PP lying on the table on the line ABAB, between AA and BB. Both strings are taut.
    Find the length APAP in equilibrium.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).