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Horizontal circular motionEdexcel International A Level Further Maths: Flashcards

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Acceleration of a particle in uniform circular motion?

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Acceleration of a particle in uniform circular motion?
v2r=rω2\frac{v^2}{r}=r\omega^2 towards the centre
Relationship between vv, rr and ω\omega?
v=rωv=r\omega
Period of circular motion in terms of ω\omega?
2πω\frac{2\pi}{\omega}
Resultant force on a particle in horizontal circular motion?
mv2r=mrω2\frac{mv^2}{r}=mr\omega^2 towards the centre
What can you say about vertical forces in horizontal circular motion?
They balance, because there is no vertical acceleration.
Conical pendulum: two equations?
Tcos⁡θ=mgT\cos\theta=mg and Tsin⁡θ=mrω2T\sin\theta=mr\omega^2
Radius of a conical pendulum circle, string length LL?
r=Lsin⁡θr=L\sin\theta
Conical pendulum: formula for ω2\omega^2?
ω2=gLcos⁡θ\omega^2=\frac{g}{L\cos\theta}, independent of mass
Hooke's law?
T=λxlT=\frac{\lambda x}{l}
Elastic string on a smooth table: radius of the circle?
r=l+xr=l+x, the stretched length
Design speed on a smooth bank?
v2=rgtan⁡αv^2=rg\tan\alpha
Direction of friction on a bank when vv is above the design speed?
Down the slope, since the vehicle tends to slide up.
Condition for a coin not to slip on a turntable?
mrω2≤μmgmr\omega^2\le\mu mg, so ω2≤μgr\omega^2\le\frac{\mu g}{r}

Exam questions on Horizontal circular motion

  1. A particle of mass 0.50.5 kg is attached to one end of a light inextensible string of length 22 m. The other end of the string is fixed to a point OO on a smooth horizontal table. The particle moves on the table in a circle with centre OO, at a constant speed of 44 m s−1^{-1}.
    The speed of the particle is increased until the tension in the string is three times its original value. Find the new speed.2 marks
  2. A particle of mass 0.40.4 kg is attached to one end of a light inextensible string of length 2.452.45 m. The other end of the string is fixed. The particle moves in a horizontal circle with constant angular speed, with the string inclined at an angle θ\theta to the vertical, where cos⁡θ=0.8\cos\theta=0.8. Take g=9.8g=9.8 m s−2^{-2}.
    Find the angular speed of the particle.2 marks
  3. A car of mass 800800 kg is modelled as a particle moving in a horizontal circle of radius 6060 m on a road banked at an angle α\alpha to the horizontal, where tan⁡α=14\tan\alpha=\frac14. Take g=9.8g=9.8 m s−2^{-2}.
    Find the speed at which the car can travel round the bend with no tendency to slip sideways.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).