Chi-squared goodness of fit testsEdexcel International A Level Further Maths: Flashcards
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What are the hypotheses in a goodness of fit test?
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- What are the hypotheses in a goodness of fit test?
- : the stated model fits the data. : it does not fit.
- State the test statistic.
- Is a goodness of fit test one-tailed or two-tailed?
- One-tailed. Only a large is evidence against the model.
- When must cells be combined?
- When any expected frequency is less than 5. Add neighbouring cells, both and .
- Degrees of freedom for goodness of fit?
- , with cells after combining and parameters estimated.
- Degrees of freedom: Poisson with estimated and 5 cells?
- Degrees of freedom: Normal with and both estimated and 6 cells?
- How is found for a fair die thrown times?
- for every face.
- How are expected frequencies found for a continuous uniform distribution on ?
- for each class.
- How is the parameter estimated for a binomial fit?
- How is the parameter estimated for a Poisson fit?
- is the sample mean. Use ' or more' for the last cell.
- What is the decision rule?
- Reject if exceeds the critical value of ; otherwise there is insufficient evidence to reject it.
- What does a very small tell you?
- The observed frequencies are very close to the model, so there is no evidence against the fit.
Exam questions on Chi-squared goodness of fit tests
- A die is thrown 120 times. Faces 1 to 6 occurred 14, 25, 17, 22, 24 and 18 times respectively. A goodness of fit test is to be used to test whether the die is fair.Calculate the value of the test statistic .2 marks
- A firm records the number of machine breakdowns in each of 100 weeks. No breakdowns occurred in 27 weeks, 1 in 35 weeks, 2 in 22 weeks, 3 in 11 weeks, 4 in 4 weeks and 5 in 1 week. The mean number of breakdowns per week is 1.33. The firm models the weekly number of breakdowns by a Poisson distribution with mean 1.33. The expected frequencies are 26.45, 35.18, 23.39, 10.37, 3.45 and 1.17 for 0, 1, 2, 3, 4 and 5 or more breakdowns respectively.Calculate the value of the test statistic for the combined cells.2 marks
- An inspector tests 120 boxes, each containing 4 bulbs, and records the number of defective bulbs in each box. There were 48 boxes with no defective bulbs, 42 with 1, 22 with 2, 7 with 3 and 1 with 4. The inspector suggests that the number of defective bulbs in a box can be modelled by , with estimated from the data.State suitable hypotheses and show that the estimate of is 0.231 to 3 significant figures.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).