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The Poisson distributionEdexcel International A Level Further Maths: Revision notes

Section 1

The Poisson model

A Poisson distribution models the number of times XX an event occurs in a fixed interval of time, length or area, when events happen randomly at a constant average rate. We write X∼Po(λ)X\sim\text{Po}(\lambda), where λ\lambda is the mean number of events in the interval. The probability function is P(X=r)=e−λλrr!,r=0,1,2,…P(X=r)=e^{-\lambda}\frac{\lambda^r}{r!},\quad r=0,1,2,\ldots Three conditions are needed: events occur independently of each other, they occur singly (never two at the same instant), and the average rate is constant. Typical examples are flaws in a roll of cloth, calls to a switchboard, or misprints per page.

Key termsPoisson distributionrateindependentsingly
Common mistake

Using the rate you were first given instead of λ\lambda for the interval in the question. Always rescale first.

Section 2

Calculating probabilities

For a single value use the formula or the calculator. For cumulative probabilities, use the Poisson tables in the formulae booklet or add the individual terms. The tables give P(X≤r)P(X\le r), so rewrite other inequalities:

  • P(X<r)=P(X≤r−1)P(X<r)=P(X\le r-1)
  • P(X≥r)=1−P(X≤r−1)P(X\ge r)=1-P(X\le r-1)
  • P(X>r)=1−P(X≤r)P(X>r)=1-P(X\le r)
  • P(a≤X≤b)=P(X≤b)−P(X≤a−1)P(a\le X\le b)=P(X\le b)-P(X\le a-1) Example: X∼Po(4)X\sim\text{Po}(4). P(X=3)=e−4433!=0.1954P(X=3)=e^{-4}\frac{4^3}{3!}=0.1954. P(X≤3)=0.4335P(X\le3)=0.4335, so P(X≥4)=1−0.4335=0.5665P(X\ge4)=1-0.4335=0.5665.
Key termscumulative probability
Exam tip

Write the inequality in terms of P(X≤r)P(X\le r) before you use the tables: it stops you being one value out.

Common mistake

Treating P(X<4)P(X<4) as P(X≤4)P(X\le4). For whole-number values, fewer than 4 means at most 3.

Section 3

Mean and variance

For X∼Po(λ)X\sim\text{Po}(\lambda) the mean and the variance both equal the parameter: E(X)=λ,Var(X)=λ.E(X)=\lambda,\qquad\text{Var}(X)=\lambda. No derivation is needed. The standard deviation is λ\sqrt\lambda. If a data set has a sample mean and variance that are about equal, that supports a Poisson model; a variance much larger than the mean suggests the events are clustered, so the model is poor.

Key termsmeanvariance

Section 4

Scaling and the additive property

If events occur at rate λ\lambda per unit, then in kk units the number of events is Po(kλ)\text{Po}(k\lambda). For example, 3 calls per minute becomes Po(15)\text{Po}(15) for 5 minutes. The additive property: if X∼Po(λ)X\sim\text{Po}(\lambda) and Y∼Po(μ)Y\sim\text{Po}(\mu) are independent, then X+Y∼Po(λ+μ)X+Y\sim\text{Po}(\lambda+\mu). This is useful for combining areas or periods, such as flaws in two separate pieces of fabric.

Key termsadditive property
Common mistake

Applying the property to a difference. X−YX-Y is not Poisson.

Exam tip

For non-overlapping intervals, treat the counts as independent and multiply their probabilities.

Section 5

Modelling and commenting critically

Exam questions often ask whether a Poisson model is appropriate. Compare each condition with the context:

  • Independence: could one event cause another, for example a breakdown causing a queue?
  • Singly: can events arrive in batches, such as a coach party arriving together?
  • Constant rate: does the rate change with the time of day, so that rush hour differs from midday? A good answer names the condition and says how the context breaks it, for example 'buses follow a timetable so arrivals are not random'. State the assumption when you use the model: 'assuming flaws occur at random at a constant rate'.
Key termsconstant rateclustering
Exam tip

Never write just 'it is not random'. Name the condition (independence, singly, constant rate) and tie it to the situation.

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Exam questions on The Poisson distribution

  1. Typing errors occur at random in a manuscript at a mean rate of 1.5 per page. The number of errors on one page is modelled by X∼Po(1.5)X\sim\text{Po}(1.5).
    Find the probability that a 2-page section contains no errors.2 marks
  2. A call centre receives calls at random at a constant mean rate of 4 calls per 10 minutes.
    Find the probability that more than 6 calls are received in a 10-minute period.2 marks
  3. Flaws occur at random in a roll of fabric at a mean rate of 0.4 per square metre. Flaws in separate pieces of fabric occur independently.
    Find the probability that a 5 m2^2 piece of fabric contains at most 3 flaws.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).