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Simultaneous equations and planesEdexcel A-Level Further Maths: Revision notes

Section 1

Solving three equations using the inverse matrix

Three linear equations in x,y,zx,y,z can be written as a matrix equation Mx=b\mathbf{M}\mathbf{x}=\mathbf{b}, where M\mathbf{M} holds the coefficients, x=(xyz)\mathbf{x}=\begin{pmatrix}x\\ y\\ z\end{pmatrix} and b\mathbf{b} holds the right-hand sides. If M\mathbf{M} is non-singular (det⁡M≠0\det\mathbf{M}\ne0), multiply both sides on the left by M−1\mathbf{M}^{-1}: x=M−1b.\mathbf{x}=\mathbf{M}^{-1}\mathbf{b}. Example: x+y+z=6x+y+z=6, 2x−y+z=32x-y+z=3, x+2y−z=2x+2y-z=2 has det⁡M=7\det\mathbf{M}=7 and solution x=1x=1, y=2y=2, z=3z=3; you can check this in all three equations. Use your calculator to find M−1\mathbf{M}^{-1} in the exam, but write the matrix equation down so the method is clear.

Key termsmatrix equationnon-singular
Common mistake

Multiplying on the wrong side. Matrices do not commute, so write x=M−1b\mathbf{x}=\mathbf{M}^{-1}\mathbf{b}, not bM−1\mathbf{b}\mathbf{M}^{-1}.

Section 2

When the method fails

If det⁡M=0\det\mathbf{M}=0 the matrix is singular and has no inverse, so the equations do not have a unique solution. There are then two possibilities:

  • the equations are consistent and have infinitely many solutions, or
  • the equations are inconsistent and have no solution. To tell which, look for a dependency. For x+2y−z=4x+2y-z=4, 2x+y+z=52x+y+z=5, 3x+3y=k3x+3y=k the first two equations add to 3x+3y=93x+3y=9. So k=9k=9 is consistent (infinitely many solutions) and any other kk is inconsistent (no solutions). The determinant is 00 for every kk.
Key termssingularconsistentinconsistent
Common mistake

Saying 'determinant is 00, so no solution'. A zero determinant means no unique solution; there may still be infinitely many.

Section 3

Planes and three equations

Each linear equation ax+by+cz=dax+by+cz=d is a plane in 3-D, with normal vector (a,b,c)(a,b,c). Solving three equations means finding the points common to three planes. Two planes are parallel when their normals are proportional: (1,2,3)(1,2,3) and (2,4,6)(2,4,6). They are coincident (the same plane) if the constants are in the same ratio too (2×5=102\times5=10), and distinct parallel planes if not (2×5≠72\times5\ne7). If det⁡M≠0\det\mathbf{M}\ne0 the three planes meet at exactly one point. If det⁡M=0\det\mathbf{M}=0 the planes are in one of the special configurations described next.

Key termsplanenormal vectorcoincident
Exam tip

Compare the coefficients of each pair of equations first: proportional coefficients mean parallel planes.

Section 4

Geometrical configurations of three planes

Consistent cases (infinitely many solutions, det⁡M=0\det\mathbf{M}=0):

  • Sheaf: three distinct planes sharing a common line, like pages meeting at a book's spine. The normals are not parallel. Example: x+2y+z=1x+2y+z=1, 2x+5y+3z=42x+5y+3z=4, 3x+7y+4z=53x+7y+4z=5 meet in the line (−3,2,0)+t(1,−1,1)(-3,2,0)+t(1,-1,1).
  • Two coincident planes and a third crossing them in a line, or all three coincident (a plane of solutions). Inconsistent cases (no solution):
  • Prism: no two planes parallel, but the planes meet pairwise in three parallel lines, with no common point. Example: x+2y−z=4x+2y-z=4, 2x+y+z=52x+y+z=5, 3x+3y=63x+3y=6.
  • Two parallel distinct planes cut by a third, or three distinct parallel planes, or two coincident planes with a parallel third. A single point arises only when det⁡M≠0\det\mathbf{M}\ne0.
Key termssheafprism
Exam tip

To tell sheaf from prism, check whether the third equation is the same combination of the first two on both sides (the constants too). If it is, sheaf; if not, prism.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Simultaneous equations and planes

  1. Three planes have equations x+y+z=6x+y+z=6,  2x−y+z=3\ 2x-y+z=3 and x+2y−z=2x+2y-z=2.
    Use the inverse of M\mathbf{M}, found using your calculator, to solve the equations.2 marks
  2. Three planes have equations x+2y−z=4x+2y-z=4,  2x+y+z=5\ 2x+y+z=5 and 3x+3y=k3x+3y=k, where kk is a constant.
    Describe the geometrical configuration of the three planes when k=6k=6, giving a reason.2 marks
  3. Three planes have equations Π1: x+2y+3z=5\Pi_1:\ x+2y+3z=5,  Π2: 2x+4y+6z=7\ \Pi_2:\ 2x+4y+6z=7 and Π3: x−y+z=1\Pi_3:\ x-y+z=1.
    Explain why the equations have no solution, and describe the geometrical configuration of the three planes.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).