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Small angle approximationsAQA A-Level Maths: Subtopic test

10 questions, 27 marks

AQA A-Level Maths

Small angle approximations

Total 27 marks

Name

Class

Date

  1. 1
    θ\theta is a small angle measured in radians.
    (a)
    Find the best small angle approximation for cos⁡4θ\cos4\theta.
    [1 mark]
    • A1−4θ21-4\theta^2
    • B1−8θ21-8\theta^2
    • C1−16θ21-16\theta^2
    • D1−2θ21-2\theta^2
    (b)
    Find the best small angle approximation for sin⁡θtan⁡2θ\sin\theta\tan2\theta.
    [1 mark]
    • A2θ2\theta
    • Bθ2\theta^2
    • C3θ23\theta^2
    • D2θ22\theta^2
    (c)
    Use small angle approximations to find an approximate value of 1−cos⁡2θθsin⁡θ\frac{1-\cos2\theta}{\theta\sin\theta}.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    An isosceles triangle ABCABC has AB=AC=10AB=AC=10 cm and BA^C=θB\hat{A}C=\theta radians, where θ\theta is small.
    (a)
    Find a small angle approximation for the length BCBC.
    [1 mark]
    • A5θ5\theta cm
    • B20θ20\theta cm
    • C10θ10\theta cm
    • D20(1−θ22)20\left(1-\frac{\theta^2}{2}\right) cm
    (b)
    Find a small angle approximation for the perpendicular distance from AA to BCBC.
    [1 mark]
    • A10−5θ2410-\frac{5\theta^2}{4} cm
    • B10−5θ210-5\theta^2 cm
    • C10−θ2810-\frac{\theta^2}{8} cm
    • D10−5θ2210-\frac{5\theta^2}{2} cm
    (c)
    Use a small angle approximation to show that the area of triangle ABCABC is approximately 50θ50\theta cm2^2.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    For small θ\theta (in radians), let f(θ)=1−cos⁡4θθtan⁡2θf(\theta)=\frac{1-\cos4\theta}{\theta\tan2\theta}.
    (a)
    Show that f(θ)≈4f(\theta)\approx4.
    [3 marks]
    (b)
    A student uses f(θ)≈4f(\theta)\approx4 when θ=0.1\theta=0.1. Use a calculator to find the exact value of f(0.1)f(0.1) and the percentage error in the student's value, relative to the exact value.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A tower of height 120120 m stands on level ground. From a point PP on the ground at a horizontal distance dd m from the base of the tower, the angle of elevation of the top is θ\theta radians, where θ\theta is small. The straight-line distance from PP to the top of the tower is LL m.
    (a)
    (i) Show that, for small θ\theta, d≈120θd\approx\frac{120}{\theta}.
    (ii) Estimate
    dd when θ=0.03\theta=0.03.
    (iii) Calculate
    dd exactly when θ=0.03\theta=0.03, and find the percentage error in your estimate from (ii).
    [6 marks]
    (b)
    (i) Show that L−d≈12Lθ2L-d\approx\frac12L\theta^2.
    (ii) Use
    θ=0.03\theta=0.03 and L≈4000L\approx4000 to estimate L−dL-d.
    (iii) A surveyor takes
    d≈Ld\approx L. Justify whether this is acceptable here.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).