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Solving exponential equationsAQA A-Level Maths: Subtopic test

10 questions, 27 marks

AQA A-Level Maths

Solving exponential equations

Total 27 marks

Name

Class

Date

  1. 1
    The equation 5x=405^x=40 is to be solved using logarithms.
    (a)
    Which expression gives the solution of 5x=405^x=40?
    [1 mark]
    • Ax=lg⁡8x=\lg8
    • Bx=lg⁡5lg⁡40x=\frac{\lg5}{\lg40}
    • Cx=lg⁡40lg⁡5x=\frac{\lg40}{\lg5}
    • Dx=lg⁡40×lg⁡5x=\lg40\times\lg5
    (b)
    Find the value of xx to 3 significant figures.
    [1 mark]
    • A2.292.29
    • B1.601.60
    • C0.4360.436
    • D88
    (c)
    Hence, or otherwise, solve 5x−1=405^{x-1}=40, giving your answer to 3 significant figures.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    £2000 is invested in an account that pays 3.5% compound interest per year. After nn complete years the value of the investment is £2000×1.035n2000\times1.035^n.
    (a)
    Which equation must be solved to find when the investment first reaches £3000?
    [1 mark]
    • A1.035n=1.51.035n=1.5
    • B1.035n=1.51.035^n=1.5
    • C2000+1.035n=30002000+1.035^n=3000
    • D2000×1.035n=15002000\times1.035^n=1500
    (b)
    What is the smallest whole number of years after which the investment is worth more than £3000?
    [1 mark]
    • A1111
    • B1515
    • C4343
    • D1212
    (c)
    Find the smallest whole number of years after which the investment is worth more than £5000.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Two equations are given: 43x−1=1004^{3x-1}=100 and 3e2x=213\mathrm{e}^{2x}=21.
    (a)
    Solve 43x−1=1004^{3x-1}=100, giving your answer to 3 significant figures.
    [3 marks]
    (b)
    Solve 3e2x=213\mathrm{e}^{2x}=21. Give the exact solution and its value to 3 significant figures.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Two bacterial cultures are studied. In culture A the number of bacteria, NAN_A, after tt hours is modelled by NA=800×1.6tN_A=800\times1.6^t. In culture B an antibiotic is added, and the number of bacteria, NBN_B, after tt hours is modelled by NB=5000×0.85tN_B=5000\times0.85^t.
    (a)
    (i) Write down the number of bacteria in culture A at t=0t=0.
    (ii) Find the time at which culture A reaches 20 000 bacteria.

    (iii) Find the time taken for culture A to double in size.

    Give your times in hours to 3 significant figures.
    [6 marks]
    (b)
    (i) Find the time at which culture B falls to 500 bacteria.
    (ii) Find the time taken for culture B to halve in size.

    (iii) State, with a reason, whether this model ever predicts that culture B has no bacteria.

    Give your times in hours to 3 significant figures.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).