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Variable acceleration in one dimensionEdexcel A-Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Further Maths

Variable acceleration in one dimension

Total 27 marks

Name

Class

Date

  1. 1
    A particle PP moves in a straight line. At time tt seconds, where t≥0t\ge0, its acceleration is (6t−12)(6t-12) m s⁻² in the positive direction. At t=0t=0, PP is at the origin OO with velocity 9 m s⁻¹ in the positive direction.
    (a)
    Find the velocity of PP when t=2t=2.
    [1 mark]
    • A−12-12 m s⁻¹
    • B00 m s⁻¹
    • C−3-3 m s⁻¹
    • D33 m s⁻¹
    (b)
    Find the displacement of PP from OO when t=2t=2.
    [1 mark]
    • A22 m
    • B−3-3 m
    • C−6-6 m
    • D−16-16 m
    (c)
    Find the times at which PP is instantaneously at rest.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A sports car accelerates from rest along a straight, level track. At time tt seconds its velocity is vv m s⁻¹ and its acceleration is 60−v20\frac{60-v}{20} m s⁻².
    (a)
    Which expression gives vv in terms of tt?
    [1 mark]
    • A60e−0.05t60e^{-0.05t}
    • B60(1−e0.05t)60\left(1-e^{0.05t}\right)
    • C60(1−e−20t)60\left(1-e^{-20t}\right)
    • D60(1−e−0.05t)60\left(1-e^{-0.05t}\right)
    (b)
    Find the time taken for the car to reach 30 m s⁻¹.
    [1 mark]
    • A20.020.0 s
    • B13.913.9 s
    • C27.727.7 s
    • D0.6930.693 s
    (c)
    Find the time taken for the car to reach 90% of its limiting speed.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A particle PP moves along the xx-axis. At time tt seconds its velocity in the positive xx-direction is 6cos⁡2t6\cos2t m s⁻¹. At t=0t=0, PP is at the point with coordinate x=1x=1. Angles are in radians.
    (a)
    Find an expression for xx in terms of tt.
    [3 marks]
    (b)
    Find the acceleration of PP when t=π3t=\frac{\pi}{3}, and the greatest value of xx.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A sledge slides in a straight line across ice and is modelled as a particle. At time tt seconds its speed is vv m s⁻¹ and its deceleration is 0.02v20.02v^2 m s⁻². At t=0t=0 its speed is 10 m s⁻¹.
    (a)
    Show that v=101+0.2tv=\frac{10}{1+0.2t}, and find the speed of the sledge when t=10t=10.
    [6 marks]
    (b)
    Find the distance travelled by the sledge in the first 10 seconds, and explain why, in this model, the sledge never comes to rest.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).