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Tests for the difference between two Normal meansEdexcel A-Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Further Maths

Tests for the difference between two Normal means

Total 27 marks

Name

Class

Date

  1. 1
    Independent random samples are taken from two Normal populations. Sample XX: nx=20n_x=20, xˉ=52.8\bar x=52.8, population variance σx2=9\sigma_x^2=9. Sample YY: ny=30n_y=30, yˉ=51.2\bar y=51.2, population variance σy2=16\sigma_y^2=16. Both variances are known.
    (a)
    Find the standard error of Xˉ−Yˉ\bar X-\bar Y.
    [1 mark]
    • A0.7070.707
    • B0.9830.983
    • C55
    • D0.9920.992
    (b)
    Calculate the test statistic for the null hypothesis H0:μx=μyH_0:\mu_x=\mu_y.
    [1 mark]
    • A1.611.61
    • B2.192.19
    • C0.320.32
    • D0.990.99
    (c)
    Test, at the 5%5\% significance level, whether the mean of XX is greater than the mean of YY. State your conclusion in context.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Reaction times, in milliseconds, are measured for two independent groups, AA and BB. Each reaction time is Normally distributed with standard deviation 4040. Group AA has 3636 people with mean time 312312. Group BB has 4949 people with mean time 298298. A researcher tests whether the mean reaction times of the two populations differ, at the 5%5\% level.
    (a)
    Which pair of hypotheses should be used?
    [1 mark]
    • AH0:xˉA=xˉBH_0:\bar x_A=\bar x_B, H1:xˉA≠xˉBH_1:\bar x_A\ne\bar x_B
    • BH0:μA=μBH_0:\mu_A=\mu_B, H1:μA≠μBH_1:\mu_A\ne\mu_B
    • CH0:μA=μBH_0:\mu_A=\mu_B, H1:μA>μBH_1:\mu_A>\mu_B
    • DH0:μA−μB=14H_0:\mu_A-\mu_B=14, H1:μA−μB≠14H_1:\mu_A-\mu_B\ne14
    (b)
    Find the pp-value of the test.
    [1 mark]
    • A0.0550.055
    • B0.8890.889
    • C0.1110.111
    • D0.9450.945
    (c)
    State the conclusion of the test, with a reason, in context.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Two classes take the same task. The times, in minutes, are not assumed to be Normal and the population variances are unknown. Class 11: n1=60n_1=60, xˉ1=24.6\bar x_1=24.6, s12=18.4s_1^2=18.4. Class 22: n2=75n_2=75, xˉ2=23.1\bar x_2=23.1, s22=22.5s_2^2=22.5. The teacher tests whether the population mean times differ.
    (a)
    Calculate the value of the test statistic for H0:μ1=μ2H_0:\mu_1=\mu_2.
    [3 marks]
    (b)
    Carry out the test at the 5%5\% significance level, and explain why a Normal distribution can be used here even though the population variances are unknown.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Two suppliers make cables. The breaking strength, in newtons, of supplier PP's cables is Normally distributed with standard deviation 1212. For supplier QQ it is Normally distributed with standard deviation 1515. A random sample of 2525 cables from PP has mean strength 187.4187.4 and a random sample of 4040 cables from QQ has mean strength 181.2181.2.
    (a)
    Test, at the 5%5\% significance level, whether the mean breaking strength of PP's cables is greater than that of QQ's cables. State your hypotheses and conclusion.
    [6 marks]
    (b)
    (i) Find the smallest difference xˉP−xˉQ\bar x_P-\bar x_Q that would lead to H0H_0 being rejected at the 5%5\% level.
    (ii) Find the smallest difference that would lead to rejection at the
    1%1\% level, and hence comment on the strength of the evidence from the observed difference of 6.26.2.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).