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Series solutions and reducible differential equationsEdexcel A-Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Further Maths

Series solutions and reducible differential equations

Total 27 marks

Name

Class

Date

  1. 1
    The function yy satisfies d2ydx2+xdydx+y=0\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2}+x\dfrac{\mathrm{d}y}{\mathrm{d}x}+y=0, with y=1y=1 and dydx=0\dfrac{\mathrm{d}y}{\mathrm{d}x}=0 at x=0x=0.
    (a)
    Find the value of d2ydx2\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2} at x=0x=0.
    [1 mark]
    • A11
    • B00
    • C−1-1
    • D−2-2
    (b)
    Which expression gives d3ydx3\dfrac{\mathrm{d}^3y}{\mathrm{d}x^3}?
    [1 mark]
    • A−xy′′−y′-xy''-y'
    • B−2y′−xy′′-2y'-xy''
    • C−2y′−xy′′−y-2y'-xy''-y
    • D−2xy′′−y′-2xy''-y'
    (c)
    Use your answer to part (b) to find the value of d4ydx4\dfrac{\mathrm{d}^4y}{\mathrm{d}x^4} at x=0x=0.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The function yy satisfies dydx=x−y2\dfrac{\mathrm{d}y}{\mathrm{d}x}=x-y^2, with y=1y=1 at x=0x=0.
    (a)
    Find the value of d2ydx2\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2} at x=0x=0.
    [1 mark]
    • A−1-1
    • B11
    • C33
    • D22
    (b)
    Find the value of d3ydx3\dfrac{\mathrm{d}^3y}{\mathrm{d}x^3} at x=0x=0.
    [1 mark]
    • A−2-2
    • B−6-6
    • C88
    • D−8-8
    (c)
    Hence find the first four terms of the series solution of the differential equation in ascending powers of xx.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The differential equation xdydx+y=xy2x\dfrac{\mathrm{d}y}{\mathrm{d}x}+y=xy^2 is to be solved for x>0x>0 using the substitution z=1yz=\dfrac1y.
    (a)
    Show that the substitution transforms the equation into dzdx−zx=−1\dfrac{\mathrm{d}z}{\mathrm{d}x}-\dfrac{z}{x}=-1.
    [3 marks]
    (b)
    Given that y=1y=1 when x=1x=1, find yy in terms of xx.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The differential equation x2d2ydx2−2xdydx+2y=4x3x^2\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2}-2x\dfrac{\mathrm{d}y}{\mathrm{d}x}+2y=4x^3 is to be solved for x>0x>0 using the substitution x=etx=\mathrm{e}^t.
    (a)
    Show that the substitution transforms the equation into d2ydt2−3dydt+2y=4e3t\dfrac{\mathrm{d}^2y}{\mathrm{d}t^2}-3\dfrac{\mathrm{d}y}{\mathrm{d}t}+2y=4\mathrm{e}^{3t}.
    [6 marks]
    (b)
    Hence find the general solution, giving yy in terms of xx.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).