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IsomorphismEdexcel A-Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Further Maths

Isomorphism

Total 27 marks

Name

Class

Date

  1. 1
    Let G={1,i,−1,−i}G=\{1,i,-1,-i\} under multiplication of complex numbers and H={0,1,2,3}H=\{0,1,2,3\} under addition modulo 4. Both are groups of order 44.
    (a)
    Which function φ:G→H\varphi:G\to H is an isomorphism?
    [1 mark]
    • Aφ(1)=0, φ(i)=2, φ(−1)=1, φ(−i)=3\varphi(1)=0,\ \varphi(i)=2,\ \varphi(-1)=1,\ \varphi(-i)=3
    • Bφ(1)=1, φ(i)=2, φ(−1)=3, φ(−i)=0\varphi(1)=1,\ \varphi(i)=2,\ \varphi(-1)=3,\ \varphi(-i)=0
    • Cφ(1)=0, φ(i)=1, φ(−1)=2, φ(−i)=3\varphi(1)=0,\ \varphi(i)=1,\ \varphi(-1)=2,\ \varphi(-i)=3
    • Dφ(1)=0, φ(i)=1, φ(−1)=3, φ(−i)=2\varphi(1)=0,\ \varphi(i)=1,\ \varphi(-1)=3,\ \varphi(-i)=2
    (b)
    Another isomorphism ψ:G→H\psi:G\to H has ψ(i)=3\psi(i)=3. What is ψ(−1)\psi(-1)?
    [1 mark]
    • A22
    • B11
    • C33
    • D00
    (c)
    Explain why no isomorphism from GG to HH can map ii to 22.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Let K={1,3,5,7}K=\{1,3,5,7\} under multiplication modulo 8 and Z4={0,1,2,3}Z_4=\{0,1,2,3\} under addition modulo 4. Both are groups of order 44.
    (a)
    Which statement shows that KK and Z4Z_4 are not isomorphic?
    [1 mark]
    • AKK is abelian but Z4Z_4 is not.
    • BKK has more elements than Z4Z_4.
    • COnly Z4Z_4 has an identity element.
    • DKK has three elements of order 22, but Z4Z_4 has only one.
    (b)
    The rotation symmetries of a square form a group RR of order 44 that is isomorphic to Z4Z_4. How many elements of RR have order 44?
    [1 mark]
    • A11
    • B22
    • C33
    • D44
    (c)
    Give a second reason, based on whether the groups are cyclic, why KK and Z4Z_4 are not isomorphic.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Let G={0,1,2,3,4,5}G=\{0,1,2,3,4,5\} under addition modulo 6 and H={1,2,3,4,5,6}H=\{1,2,3,4,5,6\} under multiplication modulo 7, both of which are groups. Define φ:G→H\varphi:G\to H by φ(k)=3k mod 7\varphi(k)=3^{k}\bmod 7.
    (a)
    Find φ(k)\varphi(k) for each k∈Gk\in G, and hence show that φ\varphi is a bijection.
    [3 marks]
    (b)
    Verify that φ(2+3)=φ(2)φ(3)\varphi(2+3)=\varphi(2)\varphi(3), and explain why φ(a+b)=φ(a)φ(b)\varphi(a+b)=\varphi(a)\varphi(b) for all a,b∈Ga,b\in G.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Let Z6={0,1,2,3,4,5}Z_6=\{0,1,2,3,4,5\} under addition modulo 6, and let S3S_3 be the group of all permutations of {1,2,3}\{1,2,3\} under composition, where xyxy means apply yy first, then xx.
    (a)
    Show that Z6Z_6 and S3S_3 are not isomorphic, using two different properties of the groups.
    [6 marks]
    (b)
    Let ω=cos⁡π3+isin⁡π3\omega=\cos\frac{\pi}{3}+i\sin\frac{\pi}{3} and let U={1,ω,ω2,ω3,ω4,ω5}U=\{1,\omega,\omega^2,\omega^3,\omega^4,\omega^5\}, the sixth roots of unity, under multiplication. Show that θ:Z6→U\theta:Z_6\to U given by θ(k)=ωk\theta(k)=\omega^k is an isomorphism.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).