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Difference between two means: pooled t-testEdexcel A-Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Further Maths

Difference between two means: pooled t-test

Total 27 marks

Name

Class

Date

  1. 1
    Independent random samples are taken from two Normal populations whose variances are equal but unknown. Sample XX has size 1010 and sample variance sx2=3.6s_x^2=3.6. Sample YY has size 1212 and sample variance sy2=6.0s_y^2=6.0. The pooled estimate of the common variance is s2s^2.
    (a)
    How many degrees of freedom does the tt statistic for testing the difference between the two population means have?
    [1 mark]
    • A2222
    • B2020
    • C2121
    • D1919
    (b)
    Find s2s^2, the pooled estimate of the common variance.
    [1 mark]
    • A4.84.8
    • B4.474.47
    • C2.222.22
    • D4.924.92
    (c)
    Find the estimated standard error of Xˉ−Yˉ\bar{X}-\bar{Y}, that is s110+112s\sqrt{\frac{1}{10}+\frac{1}{12}}, to 3 significant figures.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A pooled tt test of H0:μX=μYH_0:\mu_X=\mu_Y is carried out using independent random samples of sizes nX=6n_X=6 and nY=9n_Y=9 from two Normal populations. The sample means are xˉ=52.4\bar{x}=52.4 and yˉ=49.1\bar{y}=49.1, and the pooled estimate of the common variance is s2=11.7s^2=11.7. The test is two-tailed at the 5%5\% significance level.
    (a)
    Find the critical value that the test statistic should be compared with.
    [1 mark]
    • A±1.771\pm1.771
    • B±2.179\pm2.179
    • C±2.160\pm2.160
    • D±2.131\pm2.131
    (b)
    Which pair of assumptions is needed to justify this test?
    [1 mark]
    • AThe populations are Normal with the same (unknown) variance, and the samples are independent
    • BThe sample sizes are equal and the population variances are known
    • CThe population means are equal and the sample sizes are large
    • DThe sample variances are equal and the populations are Normal
    (c)
    Calculate the value of the test statistic.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Students solve the same puzzle using one of two methods. Eight students use method A, with times xx seconds, where ∑x=96\sum x=96 and ∑x2=1180\sum x^2=1180. Ten different students use method B, with times yy seconds, where ∑y=150\sum y=150 and ∑y2=2310\sum y^2=2310. Times for each method may be assumed to be Normally distributed with a common variance.
    (a)
    Find the pooled estimate of the common variance of the two populations.
    [3 marks]
    (b)
    Test, at the 5%5\% significance level, whether the mean times for the two methods differ. State your hypotheses and your conclusion in context.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A gardener compares two fertilisers. Nine plots are treated with fertiliser XX and eleven plots with fertiliser YY. The yields (kg per plot) have sample means xˉ=4.82\bar{x}=4.82 and yˉ=4.35\bar{y}=4.35, and unbiased sample variances sx2=0.36s_x^2=0.36 and sy2=0.49s_y^2=0.49. Yields may be assumed to be independent and Normally distributed with a common variance.
    (a)
    Test, at the 5%5\% significance level, whether fertiliser XX gives a greater mean yield than fertiliser YY. Show your working and state your conclusion in context.
    [6 marks]
    (b)
    Find a 95%95\% confidence interval for μX−μY\mu_X-\mu_Y, and state what it suggests about the difference between the fertilisers.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).