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Applications of vectors to 3-D geometryEdexcel A-Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel A-Level Further Maths

Applications of vectors to 3-D geometry

Total 27 marks

Name

Class

Date

  1. 1
    The line ll has vector equation r=(i−2j+3k)+λ(2i+j−2k)\mathbf{r}=(\mathbf{i}-2\mathbf{j}+3\mathbf{k})+\lambda(2\mathbf{i}+\mathbf{j}-2\mathbf{k}).
    (a)
    Find the direction cosines of ll, taking the direction given by the vector equation.
    [1 mark]
    • A23, 13, −23\frac23,\ \frac13,\ -\frac23
    • B2, 1, −22,\ 1,\ -2
    • C25, 15, −25\frac25,\ \frac15,\ -\frac25
    • D49, 19, 49\frac49,\ \frac19,\ \frac49
    (b)
    Which of these is an equation of ll in the form (r−a)×b=0(\mathbf{r}-\mathbf{a})\times\mathbf{b}=\mathbf{0}?
    [1 mark]
    • A(r−(2i+j−2k))×(i−2j+3k)=0\left(\mathbf{r}-(2\mathbf{i}+\mathbf{j}-2\mathbf{k})\right)\times(\mathbf{i}-2\mathbf{j}+3\mathbf{k})=\mathbf{0}
    • B(r+(i−2j+3k))×(2i+j−2k)=0\left(\mathbf{r}+(\mathbf{i}-2\mathbf{j}+3\mathbf{k})\right)\times(2\mathbf{i}+\mathbf{j}-2\mathbf{k})=\mathbf{0}
    • C(r−(i−2j+3k))×(2i+j−2k)=0\left(\mathbf{r}-(\mathbf{i}-2\mathbf{j}+3\mathbf{k})\right)\times(2\mathbf{i}+\mathbf{j}-2\mathbf{k})=\mathbf{0}
    • D(r−(i−2j+3k))⋅(2i+j−2k)=0\left(\mathbf{r}-(\mathbf{i}-2\mathbf{j}+3\mathbf{k})\right)\cdot(2\mathbf{i}+\mathbf{j}-2\mathbf{k})=0
    (c)
    Find Cartesian equations for ll.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The plane Π\Pi passes through the point A(1,2,3)A(1,2,3) and is perpendicular to the vector 2i−j+2k2\mathbf{i}-\mathbf{j}+2\mathbf{k}.
    (a)
    Find a Cartesian equation of Π\Pi.
    [1 mark]
    • A2x−y+2z=02x-y+2z=0
    • Bx+2y+3z=6x+2y+3z=6
    • C2x−y+2z=22x-y+2z=2
    • D2x−y+2z=62x-y+2z=6
    (b)
    Find the perpendicular distance from the point (4,3,−1)(4,3,-1) to Π\Pi.
    [1 mark]
    • A−1-1
    • B11
    • C33
    • D13\frac13
    (c)
    The line mm passes through the origin and has direction i+j+k\mathbf{i}+\mathbf{j}+\mathbf{k}. Find the coordinates of the point where mm meets Π\Pi.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The line ll has Cartesian equation x−13=y+2−4=z12\frac{x-1}{3}=\frac{y+2}{-4}=\frac{z}{12}, and the point PP has coordinates (5,1,0)(5,1,0).
    (a)
    Find the direction cosines of ll, and the acute angle that ll makes with the zz-axis.
    [3 marks]
    (b)
    Find the shortest distance from PP to ll.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The line ll has vector equation r=(i+j)+λ(2i+j−k)\mathbf{r}=(\mathbf{i}+\mathbf{j})+\lambda(2\mathbf{i}+\mathbf{j}-\mathbf{k}) and the plane Π\Pi has equation r⋅(i+2j+2k)=9\mathbf{r}\cdot(\mathbf{i}+2\mathbf{j}+2\mathbf{k})=9.
    (a)
    (i) Find the coordinates of the point where ll meets Π\Pi.
    (ii) Find the acute angle between
    ll and Π\Pi.
    [6 marks]
    (b)
    The point AA has position vector i+j\mathbf{i}+\mathbf{j} and lies on ll. Find the coordinates of the foot of the perpendicular from AA to Π\Pi, and hence the perpendicular distance from AA to Π\Pi.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).