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Laws of indicesAQA A-Level Maths: Flashcards

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Question

State the law for $a^m\times a^n$.

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State the law for am×ana^m\times a^n.
am+na^{m+n} (add the indices, same base).
State the law for am÷ana^m\div a^n.
am−na^{m-n} (subtract the indices, same base).
State the law for (am)n(a^m)^n.
amna^{mn} (multiply the indices).
What is a0a^0 for a≠0a\neq0?
11
What does a−na^{-n} mean?
1an\dfrac1{a^n}, the reciprocal of ana^n. It is not a negative number.
What does a1na^{\frac1n} mean?
The nnth root of aa, an\sqrt[n]{a}.
Write amna^{\frac mn} using roots.
(an)m\left(\sqrt[n]{a}\right)^m or amn\sqrt[n]{a^m}.
Evaluate 272327^{\frac23}.
(273)2=32=9\left(\sqrt[3]{27}\right)^2=3^2=9
Evaluate (49)−12\left(\dfrac49\right)^{-\frac12}.
(94)12=32\left(\dfrac94\right)^{\frac12}=\dfrac32
Write 1x\dfrac{1}{\sqrt{x}} as a power of xx.
x−12x^{-\frac12}
Simplify (8x6)23\left(8x^6\right)^{\frac23}.
4x44x^4
How do you solve x32=8x^{\frac32}=8?
Raise both sides to the power 23\frac23: x=823=4x=8^{\frac23}=4.
Why is 3x−23x^{-2} different from (3x)−2(3x)^{-2}?
3x−2=3x23x^{-2}=\dfrac3{x^2} but (3x)−2=19x2(3x)^{-2}=\dfrac1{9x^2}: the index only applies to what is directly beneath it.

Exam questions on Laws of indices

  1. A student evaluates numerical powers without a calculator, using the laws of indices.
    Evaluate (278)−23\left(\dfrac{27}{8}\right)^{-\frac23}, giving your answer as a fraction in its simplest form.2 marks
  2. Throughout this question, x>0x>0.
    Solve the equation x−32=18x^{-\frac32}=\dfrac18.2 marks
  3. The function ff is defined by f(x)=x2+3xxf(x)=\dfrac{x^{2}+3x}{\sqrt{x}} for x>0x>0.
    Write f(x)f(x) in the form xp+kxqx^{p}+kx^{q}, where pp, qq and kk are constants to be found.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).