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FrictionAQA A-Level Maths: Flashcards

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State the friction model.

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State the friction model.
F≤μRF\le\mu R, where RR is the normal reaction and μ\mu the coefficient of friction.
When is F=μRF=\mu R?
When the body is sliding, or on the point of moving (limiting equilibrium).
What direction does friction act?
Parallel to the surface, opposing motion or the tendency to move.
What is limiting friction?
The maximum friction, μR\mu R.
Does the coefficient of friction have a unit?
No, it is a pure number.
Normal reaction for a mass mm on horizontal ground with no other vertical forces?
R=mgR=mg.
Normal reaction on a slope of angle α\alpha (no other perpendicular forces)?
R=mgcos⁡αR=mg\cos\alpha.
Deceleration of a body sliding to rest on horizontal ground?
μg\mu g, independent of mass.
Condition for a block to stay at rest on a slope?
tan⁡α≤μ\tan\alpha\le\mu, i.e. mgsin⁡α≤μmgcos⁡αmg\sin\alpha\le\mu mg\cos\alpha.
What does μ=tan⁡α\mu=\tan\alpha mean for a block on a slope?
The block is in limiting equilibrium, on the point of sliding.
A rope pulls at angle θ\theta above horizontal. What is RR?
R=mg−Tsin⁡θR=mg-T\sin\theta.
How do you decide whether a body at rest starts to move?
Compare the friction needed for equilibrium with μR\mu R; if it is greater, the body moves.
What does 'smooth' mean?
μ=0\mu=0: no friction, only a normal reaction.

Exam questions on Friction

  1. A box of mass 1010 kg rests on rough horizontal ground. The coefficient of friction between the box and the ground is 0.40.4. Take g=9.8 m s−2g=9.8\ \text{m s}^{-2}.
    A horizontal force of magnitude 3030 N is applied to the box. Find the magnitude of the friction force, justifying your answer.2 marks
  2. A block of mass 55 kg is placed at rest on a rough plane inclined at 20∘20^\circ to the horizontal. The coefficient of friction between the block and the plane is 0.50.5. Take g=9.8 m s−2g=9.8\ \text{m s}^{-2}.
    Show that the block does remain at rest.2 marks
  3. A crate of mass 2020 kg is pulled from rest along rough horizontal ground by a horizontal rope with tension 9090 N. The coefficient of friction between the crate and the ground is 0.30.3. Take g=9.8 m s−2g=9.8\ \text{m s}^{-2}.
    Find the acceleration of the crate.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).