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Proof by contradictionAQA A-Level Maths: Flashcards

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What do you assume at the start of a proof by contradiction?

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What do you assume at the start of a proof by contradiction?
The negation of the statement to be proved.
How does a proof by contradiction finish?
Show the assumption leads to an impossible result, so the assumption is false and the original statement is true.
Negation of 'there are no solutions'?
There is at least one solution.
Definition of a rational number?
A number that can be written as pq\frac{p}{q} with pp, qq integers and q≠0q\neq0.
How do you start a proof that 2\sqrt2 is irrational?
Assume 2=pq\sqrt2=\frac{p}{q} with pp, qq integers having no common factor.
Why does p2=2q2p^2=2q^2 make pp even?
p2p^2 is even, and the square of an odd number is odd, so pp must be even.
What is the contradiction in the proof for 2\sqrt2?
Both pp and qq are even, so they have a common factor 2, contradicting lowest terms.
Why does p2=3q2p^2=3q^2 give pp a multiple of 3?
33 is prime and divides p2p^2, so it divides pp.
State Euclid's number.
N=p1p2⋯pn+1N=p_1p_2\cdots p_n+1
What remainder does NN leave on division by each pip_i?
Remainder 1.
Is NN in Euclid's proof always prime?
No: it is prime or has a prime factor not in the list.
How can you prove log⁡23\log_23 irrational?
Assume log⁡23=pq\log_23=\frac{p}{q}; then 3q=2p3^q=2^p, an odd number equal to an even number.
Why must the final line state the conclusion?
The proof is only complete once you say the assumption is false, so the original statement is true.

Exam questions on Proof by contradiction

  1. A student wishes to prove by contradiction that 3\sqrt3 is irrational.
    Given that p2=3q2p^2=3q^2 and pp is a multiple of 33, complete the proof that 3\sqrt3 is irrational.2 marks
  2. Claim: there are no positive integers aa and bb such that a2−b2=1a^2-b^2=1.
    Complete the proof that no such integers exist.2 marks
  3. Euclid's proof that there are infinitely many prime numbers begins by assuming that there are only finitely many, say p1,p2,…,pnp_1,p_2,\ldots,p_n, and then considers the number N=p1p2⋯pn+1N=p_1p_2\cdots p_n+1.
    Show that NN leaves remainder 11 when divided by each of p1,p2,…,pnp_1,p_2,\ldots,p_n, and state what this means for the divisibility of NN.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).