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Mathematical language, notation and argumentAQA A-Level Maths: Flashcards

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What is the difference between an equation and an identity?

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What is the difference between an equation and an identity?
An equation is true only for particular values. An identity (≡\equiv) is true for every value.
What does ⇔\Leftrightarrow mean?
If and only if: the statements imply each other.
What does ∴\therefore mean?
Therefore: introduces a conclusion.
Define the domain of a function.
The set of allowed input values.
Define the range of a function.
The set of output values the function produces.
What does A∩BA\cap B mean?
The set of elements in both AA and BB (intersection).
What does A∪BA\cup B mean?
The set of elements in AA or BB or both (union).
What does A′A' mean?
The complement: elements of the universal set not in AA.
Formula for P(A∪B)P(A\cup B)?
P(A)+P(B)−P(A∩B)P(A)+P(B)-P(A\cap B)
Set equal to A′∩B′A'\cap B'?
(A∪B)′(A\cup B)', the complement of the union.
Which sets are written N,Z,Q,R\mathbb{N},\mathbb{Z},\mathbb{Q},\mathbb{R}?
Natural numbers, integers, rational numbers and real numbers.
Why can squaring both sides of an equation produce false roots?
The step is only ⇒\Rightarrow: 12=(−1)21^2=(-1)^2, so a value that satisfies the squared equation may not satisfy the original.
Why is x2=3x⇒x=3x^2=3x\Rightarrow x=3 wrong?
Dividing by xx loses the solution x=0x=0. Factorise instead: x(x−3)=0x(x-3)=0.

Exam questions on Mathematical language, notation and argument

  1. Let A={x∈R:x2<9}A=\{x\in\mathbb{R}:x^2<9\} and B={x∈R:x≥1}B=\{x\in\mathbb{R}:x\ge1\}. The universal set is R\mathbb{R} and A′A' denotes the complement of AA.
    Write down A′∩BA'\cap B as an inequality, showing how you obtain it.2 marks
  2. The function ff is defined by f(x)=x2−4x+7f(x)=x^2-4x+7 for x∈Rx\in\mathbb{R}, x≥2x\ge2.
    The domain of ff is changed to x≥4x\ge4. Find the range of ff for this new domain, justifying your answer.2 marks
  3. A student solves x+2=x\sqrt{x+2}=x and writes: Line 1: x+2=x2x+2=x^2. Line 2: x2−x−2=0x^2-x-2=0. Line 3: (x−2)(x+1)=0(x-2)(x+1)=0. Line 4: so x=2x=2 or x=−1x=-1.
    Show that x=−1x=-1 is not a solution of the original equation, and explain how it arose.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).