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Motion in two dimensions with vectorsAQA A-Level Maths: Flashcards

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Question

State the constant acceleration formula for velocity in vector form.

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State the constant acceleration formula for velocity in vector form.
v=u+at\mathbf v=\mathbf u+\mathbf at.
State the vector formula for displacement with constant acceleration.
s=ut+12at2\mathbf s=\mathbf ut+\frac12\mathbf at^2.
How do you find the position vector from the displacement?
r=r0+s\mathbf r=\mathbf r_0+\mathbf s, adding the initial position.
Give s\mathbf s in terms of u\mathbf u, v\mathbf v and tt.
s=12(u+v)t\mathbf s=\frac12(\mathbf u+\mathbf v)t.
What is speed in terms of velocity components?
vx2+vy2\sqrt{v_x^2+v_y^2}, the magnitude of v\mathbf v.
How is velocity found from position?
v=drdt\mathbf v=\frac{d\mathbf r}{dt}, differentiating each component.
How is acceleration found from velocity?
a=dvdt=d2rdt2\mathbf a=\frac{d\mathbf v}{dt}=\frac{d^2\mathbf r}{dt^2}.
How is velocity found from acceleration?
v=∫a dt\mathbf v=\int\mathbf a\,dt, with a vector constant of integration.
How is position found from velocity?
r=∫v dt\mathbf r=\int\mathbf v\,dt, using the initial position to find c\mathbf c.
What do you need to find the constant of integration?
An initial condition, such as the velocity or position at t=0t=0.
When is a particle at rest?
When both components of the velocity are zero at the same time.
When is a particle moving parallel to i\mathbf i?
When the j\mathbf j-component of the velocity is zero (and the i\mathbf i-component is not).
What is the distance of a particle from OO?
∣r∣=x2+y2\lvert\mathbf r\rvert=\sqrt{x^2+y^2}.

Exam questions on Motion in two dimensions with vectors

  1. A particle PP moves in a horizontal plane with constant acceleration (2i−j)(2\mathbf i-\mathbf j) m s−2^{-2}, where i\mathbf i and j\mathbf j are perpendicular unit vectors. At time t=0t=0 the velocity of PP is (i+3j)(\mathbf i+3\mathbf j) m s−1^{-1} and its position vector relative to a fixed origin OO is (3i+4j)(3\mathbf i+4\mathbf j) m.
    Find the speed of PP when t=2t=2.2 marks
  2. A particle moves in a plane so that at time tt seconds its position vector relative to a fixed origin OO is r=[(t3−3t)i+(4t−t2)j]\mathbf r=\left[(t^3-3t)\mathbf i+(4t-t^2)\mathbf j\right] m, where i\mathbf i and j\mathbf j are perpendicular unit vectors.
    Find the value of tt at which the particle is moving parallel to i\mathbf i.2 marks
  3. A particle moves in a plane with acceleration a=(4t i−2j)\mathbf a=(4t\,\mathbf i-2\mathbf j) m s−2^{-2} at time tt seconds, where i\mathbf i and j\mathbf j are perpendicular unit vectors. When t=0t=0 the velocity of the particle is (2i+5j)(2\mathbf i+5\mathbf j) m s−1^{-1} and its position vector relative to a fixed origin OO is (i+3j)(\mathbf i+3\mathbf j) m.
    Find the velocity of the particle at time tt.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).