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Mathematical language, notation and argumentAQA A-Level Maths: Revision notes

Section 1

The vocabulary of algebra

A constant is a fixed value, such as 55 or π\pi. A variable is a letter that can take different values, such as xx. A term is one part of an expression, joined to others by ++ or −-, and the coefficient is the number multiplying the variable in a term. In 3x2−5x+73x^2-5x+7 the terms are 3x23x^2, −5x-5x and 77, the coefficient of xx is −5-5 and 77 is the constant term. An expression has no equals sign, such as x2+2xx^2+2x. An equation states two expressions are equal and is true only for some values, such as x2+2x=3x^2+2x=3. An identity is true for every value of the variable and is written with ≡\equiv, such as (x+1)2≡x2+2x+1(x+1)^2\equiv x^2+2x+1. An index (power) shows repeated multiplication, as in x3x^3, where 33 is the index. A function assigns exactly one output to each input.

Key termsconstantvariabletermcoefficientexpressionequationidentityindexfunction
Common mistake

Treating an identity as an equation to solve: (x+1)2≡x2+2x+1(x+1)^2\equiv x^2+2x+1 is true for every xx, so there is nothing to solve.

Section 2

Logical symbols and connecting language

Precise arguments use connecting symbols and words.

  • ⇒\Rightarrow means implies: x=3⇒x2=9x=3\Rightarrow x^2=9 (true), but the reverse fails because xx could be −3-3.
  • ⇐\Leftarrow means "is implied by", and ⇔\Leftrightarrow means if and only if: both directions hold, as in 2x+1=7⇔x=32x+1=7\Leftrightarrow x=3.
  • ∴\therefore means "therefore", used when concluding a line of working.
  • ≡\equiv is used for identities. Words such as "so", "hence", "because" and "since" must connect lines logically. An argument should move from given assumptions through justified steps to a conclusion, and diagrams or sketched graphs are used where they help to justify a step. A statement such as x2=4⇒x=2x^2=4\Rightarrow x=2 is false as a deduction, because x=−2x=-2 also satisfies the left-hand side.
Key termsimpliesif and only ifthereforeconverse
Common mistake

Writing ⇔\Leftrightarrow when a step only goes one way, such as squaring both sides: x=2⇒x2=4x=2\Rightarrow x^2=4, but not the reverse.

Section 3

Set notation, inequalities and probability

A set is a collection of elements written in braces, {1,2,3}\{1,2,3\}. Set-builder notation {x∈R:x>2}\{x\in\mathbb{R}:x>2\} means "the set of real xx such that x>2x>2".

  • x∈Ax\in A: xx is an element of AA. x∉Ax\notin A: it is not.
  • A∪BA\cup B (union): in AA or BB or both. A∩BA\cap B (intersection): in both.
  • A′A' (complement): everything in the universal set ξ\xi that is not in AA. ∅\emptyset is the empty set. A⊂BA\subset B: AA is a subset of BB.
  • Number sets: N\mathbb{N} (natural), Z\mathbb{Z} (integers), Q\mathbb{Q} (rational), R\mathbb{R} (real). Inequalities describe sets: with A={x:−3<x<3}A=\{x:-3<x<3\} and B={x:x≥1}B=\{x:x\ge1\}, A∩B={x:1≤x<3}A\cap B=\{x:1\le x<3\} and A∪B={x:x>−3}A\cup B=\{x:x>-3\}. In probability, A∩BA\cap B is "AA and BB" and A∪BA\cup B is "AA or BB", with P(A∪B)=P(A)+P(B)−P(A∩B).P(A\cup B)=P(A)+P(B)-P(A\cap B). Also P(A′)=1−P(A)P(A')=1-P(A) and (A∪B)′=A′∩B′(A\cup B)'=A'\cap B'.
Key termsunionintersectioncomplementempty setsubsetuniversal set
Exam tip

Draw a quick number line or Venn diagram before combining sets; most boundary errors are visible at once.

Section 4

Functions, domain and range

A function is a rule that gives exactly one output for each input. We write f(x)=…f(x)=\ldots or f:x↦…f:x\mapsto\ldots. The domain is the set of allowed inputs and the range is the set of outputs that result. A relation where one input gives two outputs (such as y=±xy=\pm\sqrt x) is not a function. The domain may be restricted by the context or by the problem: x−1\sqrt{x-1} needs x≥1x\ge1 and 1x−2\frac{1}{x-2} needs x≠2x\ne2. Worked example: f(x)=x2−4x+7f(x)=x^2-4x+7 for x≥2x\ge2. Completing the square, f(x)=(x−2)2+3f(x)=(x-2)^2+3. The minimum is at x=2x=2, where f=3f=3, and ff increases for x≥2x\ge2, so the range is f(x)≥3f(x)\ge3. If the domain were x≥4x\ge4 the range would be f(x)≥7f(x)\ge7, because f(4)=7f(4)=7. Changing the domain changes the range.

Key termsfunctiondomainrangemapping
Common mistake

Quoting the range of a restricted function as if the domain were all real numbers. Check the domain first.

Section 5

Comprehending and critiquing arguments

A good argument is valid at every line. When critiquing a proof or a solution, look for:

  • steps that are only ⇒\Rightarrow but are written as ⇔\Leftrightarrow, such as squaring both sides, which can add false roots (x+2=x\sqrt{x+2}=x gives x=2x=2 and a false root x=−1x=-1);
  • dividing by an expression that could be zero, which loses solutions: x2=3xx^2=3x gives x=0x=0 or x=3x=3, not just x=3x=3;
  • a claim "proved" from a few examples: examples support a statement but do not prove it, although one counter-example disproves it;
  • answers that ignore the domain or context, such as a negative length;
  • unjustified use of a diagram or graph. When you check a method or formula, ask what assumptions it needs and whether each step follows from the one before.
Key termsvalidfalse rootcounter-example
Exam tip

After any solve that involved squaring or a square root, substitute every answer back into the original equation.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Mathematical language, notation and argument

  1. Let A={x∈R:x2<9}A=\{x\in\mathbb{R}:x^2<9\} and B={x∈R:x≥1}B=\{x\in\mathbb{R}:x\ge1\}. The universal set is R\mathbb{R} and A′A' denotes the complement of AA.
    Write down A′∩BA'\cap B as an inequality, showing how you obtain it.2 marks
  2. The function ff is defined by f(x)=x2−4x+7f(x)=x^2-4x+7 for x∈Rx\in\mathbb{R}, x≥2x\ge2.
    The domain of ff is changed to x≥4x\ge4. Find the range of ff for this new domain, justifying your answer.2 marks
  3. A student solves x+2=x\sqrt{x+2}=x and writes: Line 1: x+2=x2x+2=x^2. Line 2: x2−x−2=0x^2-x-2=0. Line 3: (x−2)(x+1)=0(x-2)(x+1)=0. Line 4: so x=2x=2 or x=−1x=-1.
    Show that x=−1x=-1 is not a solution of the original equation, and explain how it arose.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).