All revision notes topics

Language of kinematics and motion graphsEdexcel A-Level Maths: Revision notes

Section 1

The language of kinematics

Kinematics describes motion without considering its causes. Learn the distinctions:

  • position: where an object is, relative to a fixed origin
  • displacement: change in position, a vector (it has direction and sign)
  • distance travelled: total length of path, always positive
  • velocity: rate of change of displacement, a vector
  • speed: magnitude of velocity, always positive
  • acceleration: rate of change of velocity, a vector Average speed =total distancetime=\frac{\text{total distance}}{\text{time}} and average velocity =displacementtime=\frac{\text{displacement}}{\text{time}}. If the direction reverses, distance is larger than the magnitude of displacement.
Key termsdisplacementdistance travelledvelocityspeedaccelerationvector
Common mistake

Giving distance or speed as negative. Only displacement, velocity and acceleration can be negative.

Section 2

Displacement--time graphs

On a displacement--time graph:

  • the gradient at a point is the velocity at that time
  • a straight line means constant velocity
  • a horizontal line means the object is at rest
  • a negative gradient means motion in the negative direction
  • a curve means the velocity is changing The graph shows displacement from the origin, not distance travelled. When the graph reaches its highest or lowest point, the velocity is zero as the object changes direction.
Key termsgradientat rest
Common mistake

Reading the displacement--time graph as if it were the path of the object.

Section 3

Velocity--time graphs

On a velocity--time graph:

  • the gradient is the acceleration
  • the area between the graph and the time axis is the displacement
  • area below the axis counts as negative displacement
  • a horizontal line is constant velocity (zero acceleration) For distance travelled, add the magnitudes of the areas above and below the axis. Split areas into rectangles and triangles, or use the trapezium area 12(a+b)h\frac12(a+b)h.
Key termsarea under graphtrapezium
Exam tip

Read the question for distance or displacement. If the graph crosses the time axis, treat the parts separately.

Section 4

Using the graphs

Worked example. A train accelerates uniformly from 00 to 2020 m s−1^{-1} in 10 s, then travels at 2020 m s−1^{-1} for 30 s, then slows uniformly to rest in 20 s.

  • Final acceleration: gradient =0−2020=−1=\frac{0-20}{20}=-1 m s−2^{-2}.
  • Distance: 12(10)(20)+30(20)+12(20)(20)=100+600+200=900\frac12(10)(20)+30(20)+\frac12(20)(20)=100+600+200=900 m.
  • Average speed: 90060=15\frac{900}{60}=15 m s−1^{-1}. Graphical solutions may be required: for example, finding when two objects have the same velocity, or the time at which a displacement is reached.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Language of kinematics and motion graphs

  1. A runner jogs 300 m east from a point OO in 100 s, then turns and jogs 100 m west in 50 s, all in a straight line. Take east as the positive direction.
    Find the average speed for the whole run, and explain why it is not equal to the magnitude of the average velocity.2 marks
  2. A train moves along a straight track. Its velocity increases uniformly from 00 to 2020 m s−1^{-1} in 10 s, stays constant at 2020 m s−1^{-1} for 30 s, then decreases uniformly to rest in 20 s. Consider its velocity--time graph.
    Find the average speed of the train over the whole journey.2 marks
  3. A particle PP moves on a straight line through a fixed point OO. Its displacement from OO is ss metres at time tt seconds. At t=0t=0, s=2s=2. From t=0t=0 to t=4t=4, PP moves with constant velocity to s=14s=14. From t=4t=4 to t=7t=7, PP is at rest. From t=7t=7 to t=12t=12, PP moves with constant velocity to s=−6s=-6.
    Find the velocity of PP in each of the three stages of its motion.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).