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Manipulating and factorising polynomialsEdexcel International A Level Maths: Revision notes

Section 1

Polynomials and notation

A polynomial is a sum of terms of the form axnax^n with nn a non-negative integer. Its degree is the highest power of xx, e.g. x3+4x2+3xx^3+4x^2+3x has degree 33. The notation f(x)f(x) names the polynomial and f(a)f(a) means 'substitute x=ax=a'. For f(x)=x3+4x2+3xf(x)=x^3+4x^2+3x, f(−2)=−8+16−6=2f(-2)=-8+16-6=2. Take care with negative numbers: use brackets, (−2)3=−8(-2)^3=-8.

Key termspolynomialdegreecoefficient
Common mistake

Writing (−2)2(-2)^2 as −4-4. Use brackets when substituting negative values.

Section 2

Expanding brackets and collecting like terms

Multiply every term in one bracket by every term in the next, then collect like terms (same power of xx). Example: (2x−1)(x+3)2(2x-1)(x+3)^2. First (x+3)2=x2+6x+9(x+3)^2=x^2+6x+9. Then (2x−1)(x2+6x+9)=2x3+12x2+18x−x2−6x−9=2x3+11x2+12x−9(2x-1)(x^2+6x+9)=2x^3+12x^2+18x-x^2-6x-9=2x^3+11x^2+12x-9. A cube such as (x−2)3(x-2)^3 is done in two steps: (x−2)2=x2−4x+4(x-2)^2=x^2-4x+4, then multiply by (x−2)(x-2) to get x3−6x2+12x−8x^3-6x^2+12x-8.

Key termslike terms
Common mistake

Squaring a bracket as (x+3)2=x2+9(x+3)^2=x^2+9. Always write it out as (x+3)(x+3)(x+3)(x+3).

Exam tip

Check an expansion by substituting x=1x=1 in the original and the expanded form.

Section 3

Factorising: common factors and quadratics

Always look for a common factor first. For x3+4x2+3xx^3+4x^2+3x, take out xx: x(x2+4x+3)x(x^2+4x+3). Then factorise the quadratic: x(x+1)(x+3)x(x+1)(x+3). A quadratic x2+bx+cx^2+bx+c factorises as (x+p)(x+q)(x+p)(x+q) with p+q=bp+q=b and pq=cpq=c. For ax2+bx+cax^2+bx+c, find two numbers with product acac and sum bb, then split the middle term. A factorised polynomial must be fully factorised: x(x2+4x+3)x(x^2+4x+3) is not finished.

Key termscommon factorfully factorised
Exam tip

After factorising, expand your answer mentally to check.

Section 4

Difference of two squares and cubics

The difference of two squares: a2−b2=(a−b)(a+b)a^2-b^2=(a-b)(a+b). So x2−9=(x−3)(x+3)x^2-9=(x-3)(x+3), and x3−9x=x(x2−9)=x(x−3)(x+3)x^3-9x=x(x^2-9)=x(x-3)(x+3). For a cubic with no constant term, such as 2x3−8x2+6x2x^3-8x^2+6x, take out the common factor 2x2x to leave a quadratic: 2x(x2−4x+3)=2x(x−1)(x−3)2x(x^2-4x+3)=2x(x-1)(x-3). Polynomials of degree up to 33 at this level factorise by common factor, then a quadratic or the difference of two squares.

Key termsdifference of two squares
Common mistake

Trying to factorise a sum of two squares such as x2+9x^2+9: it does not factorise over the real numbers.

Section 5

Using polynomials in context

In context problems, form an expression for a volume or area, expand and simplify, then factorise to reveal structure. A box with square base side (x+2)(x+2) and height (2x−1)(2x-1) has volume (x+2)2(2x−1)=2x3+7x2+4x−4(x+2)^2(2x-1)=2x^3+7x^2+4x-4. Total surface area =2(x+2)2+4(x+2)(2x−1)=10x2+20x=10x(x+2)=2(x+2)^2+4(x+2)(2x-1)=10x^2+20x=10x(x+2). Subtracting one polynomial from another: remove the brackets carefully, changing every sign inside the bracket being subtracted.

Common mistake

Subtracting a bracket and changing only the first sign: −(x3+3x2−4)-(x^3+3x^2-4) changes all three terms.

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Exam questions on Manipulating and factorising polynomials

  1. The polynomial f(x)=x3+4x2+3xf(x)=x^3+4x^2+3x is defined for real xx.
    Solve f(x)=0f(x)=0.2 marks
  2. The function g(x)=(2x−1)(x+3)2g(x)=(2x-1)(x+3)^2 is defined for real xx.
    Show that g(x)=2x3+11x2+12x−9g(x)=2x^3+11x^2+12x-9.2 marks
  3. The polynomials h(x)=x3−9xh(x)=x^3-9x and k(x)=x2−x−12k(x)=x^2-x-12 are defined for real xx.
    Factorise h(x)h(x) completely.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).